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mylen [45]
3 years ago
6

You are on a train moving east at 100 meters/second. You run down the aisle at 10 meters/second. If you are running in the same

direction as the train (east), what is your speed with respect to the ground?
Physics
1 answer:
VladimirAG [237]3 years ago
8 0

Answer:

I'm pretty sure your speed relative to the ground would be 110 meters per second. However that is just a guess and I'm not 100% sure.

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A 110 V power line is protected by a 15 A fuse. What is the maximum number of 400 W lamps that can be simultaneously operated in
Nitella [24]

Answer:

Total number of lamps will be 4            

Explanation:

We have given power of the lamp W = 400 watt

Potential difference across the lamp V=110 volt

We know that power is equal to P=VI

So 400=110\times I

I=3.636A

Total current is given 15 A

As it is given that lamps are connected in parallel so total current is the sum of current through each lamp

So number of lamp will be n=\frac{15}{3.636}=4.125

As the lamp can not be in negative

So total number of lamps will be 4

5 0
3 years ago
a machine gun fires 10 rounds per second the speed of the bullets is 300 m/s. what is the distance in the air between the flying
vovangra [49]
<span>(300 m/s)/(10 r/s) = 30 m/round.</span>
4 0
3 years ago
The figure shows a graph of electric potential versus position along the x-axis. A proton is originally at point A, moving along
Lostsunrise [7]
Can we see the figure?
5 0
3 years ago
what is the force of gravity attraction between an object with a mass of 0.5 kg and another object has a mass of 0.33 kg and a d
elena55 [62]

Answer:

from \: newton \: law \: of \: gravitation \\ F =  \frac{GMm}{ {r}^{2} }  \\ G = 6.67 \times  {10}^{ - 11}  \\ M = 0.5 \: kg \\ m = 0.33 \: kg \\ r = 0.002 \: m \\ substitute \\ F =  \frac{(6.67 \times  {10}^{ - 11}) \times (0.5) \times (0.33)) }{ {(0.002)}^{2} }  \\  = 2.75 \times  {10}^{ - 6} N

4 0
3 years ago
When the displacement in SHM is equal to 1/3 of the amplitude xm, what fraction of the total energy is (a) kinetic energy and (b
Nesterboy [21]

Answer:

Explanation:

Given

Displacement is \frac{1}{3} of Amplitude

i.e. x=\frac{A}{3} , where A is maximum amplitude

Potential Energy is given by

U=\frac{1}{2}kx^2

U=\frac{1}{2}k(\frac{A}{3})^2

U=\frac{1}{18}kA^2

Total Energy of SHM is given by

T.E.=\frac{1}{2}kA^2

Total Energy=kinetic Energy+Potential Energy

K.E.=\frac{1}{2}kA^2 -\frac{1}{18}kA^2

K.E.=\frac{8}{18}kA^2

Potential Energy is \frac{1}{8} th of Total Energy

Kinetic Energy is \frac{8}{9} of Total Energy

(c)Kinetic Energy is 0.5\times \frac{1}{2}kA^2

P.E.=\frac{1}{4}kA^2

\frac{1}{2}kx^2=\frac{1}{4}kA^2

x=\frac{A}{\sqrt{2}}                  

7 0
4 years ago
Read 2 more answers
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