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natta225 [31]
3 years ago
6

Two forces, one of which double the other has resultant of 280N. if the direction of the large force is reversed and the remaini

ng unaltered, the resultant reduces to 160N. determine the magnitude of the force and the angle between the forces.
A body weighing 210N is resting on a horizontal table.A pull of 70 applied at an angle of 21 with the horizontal just causes the body to slide over the table. calculate the normal reaction and the coefficient of friction.​
Engineering
1 answer:
White raven [17]3 years ago
4 0

Answer:

point is 16 N.If their resultant is normal to the smaller force and has a magnitude of 8 N. Then two forces are.

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A CL soil is being used for compacted fill on a project. A sample of the compacted soil with a total volume of 1/30 ft3 weighs 4
Genrish500 [490]

Answer:

A. 0.4

B. 1.003

C. 0.83

Explanation:

The void ratio of a mixture is defined as the ratio of the volume of voids to volume of solids.

Total volume of soil = 1/30 ft3

= 1 ft3/30 * 0.0283 m3/1 ft3

= 9.43 x 10^-4 m3

Mass of water is in the soil = 20% * 4.8

= 0.96 pounds of water

= 0.96 * 0.454

= 0.44 kg

SG = density of substance/density of water

= 2.66 * 1 kg/l

Density of the soil = 2.660 kg/l

Mass of solid = 80 %

= 80% * 4.8 * 0.454

= 1.74 kg

Volume of solids = mass/density

= 1.74/2.66

= 6.63 l

= 6.63 x 10^-4 m3.

The volume of voids is found by adding the volume of water and the volume of air.

Total volume of soil = volume of (solids + voids)

9.43 x 10^-4 = 6.63 x 10^-4 + voids

Volume of voids = 2.8 x 10^-4 m3

A.

Void ratio = volume of void : volume of solids

= 2.8 : 6.63

= 0.4

B.

Y = (1 + w) * Gs * Yw * (1 + e)

Y = moist unit weight

Yw = unit weight of water

w = moisture content of the material

Gs = pecific gravity of the solid

e = void ratio

= (1 + 0.2) * 2.66 * 0.44 * (1 + 0.4)

= 1.003.

C.

gd = Y/(1 + w)

Or

= Gs * Yw * 1/(1 + e)

= 0.83.

6 0
3 years ago
To analyze and design a passive, first-order high-pass filter using a series RC circuit. An instrument needs to detect periodic
olga nikolaevna [1]

Answer:

R= 53.7 Ω

Explanation:

fc= 1/(2πRC)

3000=1/(2π× 1 × 10^-6 × R)

R= 53.7 Ω

6 0
3 years ago
(a) The reverse-saturation current of a pn junction diode is IS = 10−11 A. Determine the diode voltage to produce currents of (i
kirill115 [55]

Answer:

The equation used to solve a diode is

i_d = I_se^\frac{V_d}{V_T}-1

  • i_d is the current going through the diode
  • I_s is your saturation current
  • V_D is the voltage across your diode
  • V_T is the voltage of the diode at a certain room temperature. by default, you always use V_T=25.9mV for room temperature.

If you look at the equation, i_d = I_se^\frac{V_d}{V_T}-1, you'd notice that the e^\frac{V_d}{V_T} grow exponentially fast, so we can ignore the -1 in the equation because it's so small compared to the exponential.

i_d = I_se^\frac{V_d}{V_T}-1

i_d\approx I_se^\frac{V_d}{V_T}

Therefore, use i_d= I_se^\frac{V_d}{V_T} to solve your equation.

Rearrange your equation to solve for V_D.

V_D=V_Tln(\frac{i_D}{I_s})

a.)

i.)

You're given I_s=10^{-11}A

at i_d=10\mu A,     V_D=V_Tln(\frac{i_D}{I_s})=(25.9\cdot10^{-3})ln(\frac{10\cdot10^{-6}}{10\cdot10^{-11}})=.298V

at i_d=100\mu A,   V_D=V_Tln(\frac{i_D}{I_s})=(25.9\cdot10^{-3})ln(\frac{100\cdot10^{-6}}{10\cdot10^{-11}})=.358V

at i_d=1mA,      V_D=V_Tln(\frac{i_D}{I_s})=(25.9\cdot10^{-3})ln(\frac{1\cdot10^{-3}}{10\cdot10^{-11}})=.417V

<em>note: always use</em>  V_T=25.9mV

ii.)

Just repeat part (i) but change to I_s=-5\cdot10^{-12}A

b.)

same process as part A. You do the rest of the problem by yourself.

4 0
3 years ago
How is tolerance calculated?
blondinia [14]

Answer:

hope you like it brainliest plezz

Explanation:

Tolerance equals the difference between lower and upper limit dimensions. Example; for 0.500-0.506 inch the tolerance would be 0.006 inch. BILATERAL TOLERANCE : It is a way to express tolerance by using both minus and plus variations from a given size.

3 0
3 years ago
A three-phase 12 HP motor is 90% efficient with a .89 lagging power factor. What is the required rated input apparent power for
Feliz [49]

Answer:

The required rated input apparent power is 14.98 HP

Explanation:

Real power input = real power output ÷ efficiency

real power output = 12 HP

efficiency = 90% = 0.9

Real power input = 12 ÷ 0.9 = 13.33 HP

Apparent power input = real power input ÷ power factor = 13.33 ÷ 0.89 = 14.98 HP

5 0
3 years ago
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