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VMariaS [17]
3 years ago
13

Suppose that we have a 1000 pF parallel-plate capacitor with air dielectric charged to 1000 V. The capacitors terminals are open

circuited. Find the stored energy. If the plates are moved apart so that d is doubled, determine the new voltage on the capacitor and the new stored energy. Where did the extra energy come from?

Engineering
1 answer:
AlekseyPX3 years ago
8 0

Answer:

A) initial stored energy = 5x10^-4 J

B) new voltage if space is doubled will be 2000V

C) if space is doubled, stored energy becomes 2x10^-3 J

D) the extra energy comes from the work done in moving the plates further apart

Explanation:

Detailed explanation and calculation is shown in the image below

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A nozzle receives an ideal gas flow with a velocity of 25 m/s, and the exit at 100 kPa, 300 K velocity is 250 m/s. Determine the
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Given Information:

Inlet velocity = Vin = 25 m/s

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Required Information:

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Inlet Temperature of argon = 360K

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Explanation:

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$ C_p(T_{in} - T_{out}) = \frac{1}{2} \times (V_{out}^2 - V_{in}^2) $

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$ T_{in}  = \frac{1}{2} \times \frac{(V_{out}^2 - V_{in}^2)}{C_p}  + T_{out}$

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The specific heat constant of argon is given by (from ideal gas properties table)

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$ T_{in}  = \frac{1}{2} \times \frac{(250^2 - 25^2)}{520}  + 300$

$ T_{in}  = \frac{1}{2} \times 119  + 300$

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For Helium Gas:

The specific heat constant of helium is given by (from ideal gas properties table)

C_p = 5193 \:\: J/kg.K

So, the inlet temperature of helium is

$ T_{in}  = \frac{1}{2} \times \frac{(250^2 - 25^2)}{5193}  + 300$

$ T_{in}  = \frac{1}{2} \times 12  + 300$

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For Nitrogen Gas:

The specific heat constant of nitrogen is given by (from ideal gas properties table)

C_p = 1039 \:\: J/kg.K

So, the inlet temperature of nitrogen is

$ T_{in}  = \frac{1}{2} \times \frac{(250^2 - 25^2)}{1039}  + 300$

$ T_{in}  = \frac{1}{2} \times 60  + 300$

$ T_{in}  = 330K $

Note: Answers are rounded to the nearest whole numbers.

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