Suppose that we have a 1000 pF parallel-plate capacitor with air dielectric charged to 1000 V. The capacitors terminals are open
circuited. Find the stored energy. If the plates are moved apart so that d is doubled, determine the new voltage on the capacitor and the new stored energy. Where did the extra energy come from?
1 answer:
Answer:
A) initial stored energy = 5x10^-4 J
B) new voltage if space is doubled will be 2000V
C) if space is doubled, stored energy becomes 2x10^-3 J
D) the extra energy comes from the work done in moving the plates further apart
Explanation:
Detailed explanation and calculation is shown in the image below
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Explanation:
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Answer:
Explanation:
From the question we are told that:
Initial Pressure
Initial Temperature
Final Pressure
Final Temperature
Work Output
Generally Specific Energy from table is
At initial state
With
Specific Volume
At Final state
Generally the equation for The Process is mathematically given by
Assuming Mass to be Equal
Where
Therefore