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VMariaS [17]
3 years ago
13

Suppose that we have a 1000 pF parallel-plate capacitor with air dielectric charged to 1000 V. The capacitors terminals are open

circuited. Find the stored energy. If the plates are moved apart so that d is doubled, determine the new voltage on the capacitor and the new stored energy. Where did the extra energy come from?

Engineering
1 answer:
AlekseyPX3 years ago
8 0

Answer:

A) initial stored energy = 5x10^-4 J

B) new voltage if space is doubled will be 2000V

C) if space is doubled, stored energy becomes 2x10^-3 J

D) the extra energy comes from the work done in moving the plates further apart

Explanation:

Detailed explanation and calculation is shown in the image below

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      boolean lengthCheck = true;

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      }

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      for (int i = 0; i < length; i++)

      {

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*/

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      int j=0;

      for (int i = 0; i < length; i++)

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      System.out.println("\n");

     

  }

}

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