Answer:
ummm why is you doing this
Explanation:
It doesnt make sense.
The Pareto principle is that most things in our life are not commonly distributed.
<u>Explanation:</u>
Pareto chart shows that most of the things which we have in our life and the resources in our life are not equally distributed. The ratio is not always 50:50 according to this principle.
The most important use of a Pareto diagram is to show the most important factor among the set of factors that have been shown. Along with that it also shows the sources which lead to the common defects in the system and tries to solve those defects which occur most often.
Broken yellow b/c you can’t pass on a double solid yellow
Answer:
a. 0.28
Explanation:
Given that
porosity =30%
hydraulic gradient = 0.0014
hydraulic conductivity = 6.9 x 10⁻4 m/s
We know that average linear velocity given as
![v=\dfrac{K}{n_e}\dfrac{dh}{dl}](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7BK%7D%7Bn_e%7D%5Cdfrac%7Bdh%7D%7Bdl%7D)
![v=\dfrac{6.9\times 10^{-4}}{0.3}\times0.0014\ m/s](https://tex.z-dn.net/?f=v%3D%5Cdfrac%7B6.9%5Ctimes%2010%5E%7B-4%7D%7D%7B0.3%7D%5Ctimes0.0014%5C%20m%2Fs)
![v=3.22\times 10^{-6}\ m/s](https://tex.z-dn.net/?f=v%3D3.22%5Ctimes%2010%5E%7B-6%7D%5C%20m%2Fs)
The velocity in m/d ( 1 m/s =86400 m/d)
v= 0.27 m/d
So the nearest answer is 'a'.
a. 0.28
Answer:
7.7 kN
Explanation:
The capacity of a material having a crack to withstand fracture is referred to as fracture toughness.
It can be expressed by using the formula:
![K = \sigma Y \sqrt{\pi a}](https://tex.z-dn.net/?f=K%20%3D%20%5Csigma%20Y%20%5Csqrt%7B%5Cpi%20a%7D)
where;
fracture toughness K = 137 MPa![m^{1/2}](https://tex.z-dn.net/?f=m%5E%7B1%2F2%7D)
geometry factor Y = 1
applied stress
= ???
crack length a = 2mm = 0.002
∴
![137 =\sigma \times 1 \sqrt{ \pi \times 0.002 }](https://tex.z-dn.net/?f=137%20%3D%5Csigma%20%5Ctimes%201%20%20%5Csqrt%7B%20%5Cpi%20%5Ctimes%200.002%20%7D)
![137 =\sigma \times 0.07926](https://tex.z-dn.net/?f=137%20%3D%5Csigma%20%5Ctimes%200.07926)
![\dfrac{137}{0.07926} =\sigma](https://tex.z-dn.net/?f=%5Cdfrac%7B137%7D%7B0.07926%7D%20%3D%5Csigma)
![\sigma = 1728.489 MPa](https://tex.z-dn.net/?f=%5Csigma%20%3D%201728.489%20MPa)
Now, the tensile impact obtained is:
![\sigma = \dfrac{P}{A}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cdfrac%7BP%7D%7BA%7D)
P = A × σ
P = 1728.289 × 4.5
P = 7777.30 N
P = 7.7 kN