Tell whether the ordered pair is a solution of the equation! please help i will mark you brainliest

Mathematics

1 answer:

larisa86 [58]2 years ago

5 0

Answer:

the answer is

yes to 7 and no to 10

Step-by-step explanation:

7. y = 3x---------> 2*3 = 6

10. y = 7x+2--------------> 2*7=14--> 14+2 = 16

16 does not equal 0

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Can you please help answer will make you brainliest

Nady [450]

Answer:

Step-by-step explanation:

given a triangle with 2 sides and the angle between them given, then the area (A) is calculated as

A = $\frac{1}{2}$ bc sinA

the 2 sides are b = 4, c = 6 and ∠ A = 35° , then

A = $\frac{1}{2}$ × 4 × 6 × sin35° = 12 × sin35° ≈ 6.9 m² ( to the nearest tenth )

7 0

1 year ago

PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.

Liula [17]

Answer:

$\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}$

Step-by-step explanation:

$\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)$

$\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)$