Answer: The first experiment has M probabilities, and the second has I(m) outcomes, that depends on the result of the first.
And lets call m to the result of the first experiment.
If the outcome of the first experiment is 1, then the second experiment has 1 possible outcome.
If the outcome of the first experiment is 2, then the second experiment has 2 possibles outcomes.
If the outcome of the first experiment is M, then the second experiment has M possibles outcomes.
And so on.
So the total number of combinations C is the sum of all the cases, where we exami
1 outcome for m = 1
+
2 outcomes for m=2
+
.
.
.
+
M outcomes for m = M
C = 1 + 2 + 3 + 4 +...´+M
They are abstract "word" problems, offered for the purpose of giving the
student of high school mathematics valuable practice in the application
and manipulation of the concept of "percent".
Often, some time spent in solving practice-examples such as these can
lead to the phenomenon known as "learning", whereby the student comes
to know, understand, and possess competence in a topic where he or she
was previously ignorant and incompetent.
It is important to realize that the practice is the vital component in the process,
whereas the answers alone have no value at all.
Where are the statements please?
Answer:
its Dec. 25 and its used to celebrate the birth of Christ
Step-by-step explanation:
Answer:
x≤5
Step-by-step explanation:
-10(9-2x)-x≤2x-5
-90+20x-x≤2x-5
19x-2x≤90-5
17x≤85
x≤85/17
x≤5
