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Ber [7]
3 years ago
13

a $35 decrease followed by a $25 increase is it same as the origional price,is it less the the origional ,or is it greater than

the origional
Mathematics
1 answer:
velikii [3]3 years ago
8 0
It is less than original
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Write -4x^2-16x-14 in vertex form.
frutty [35]

Answer:

(-2,2)

Step-by-step explanation:

hope this helps :)

5 0
3 years ago
Anybody good at geometry
Butoxors [25]
I gotchu bruh.
Equilateral triangles got 60 per angle
Add 60 to that one next to 100 so you got 160 and the other triangle is iscosles so the equation is
160+60+60+x+x=360
2x=80
X=40
5 0
4 years ago
Which situation is most likely to have a constant rate of change
Alekssandra [29.7K]
The answer is:

B. The cost for a group of friends to see a movie compared to the number of friends.

We can tell that this is most likely to have a constant rate of change because of what we already know about movie prices.

Movie prices are fixed, therefore, no matter how many friends you bring, the total price will always go up by the same amount.

For example:

Let's say a movie ticket costs $5 and you brought 3 friends with you. Since there are 4 people in total, you'd have to pay $20 for the tickets (5x4=20). Just as you're about to pay, Sally shows up. Now you have to pay for 5 people in total. How much do you need to pay now?

You will now need to pay $25 (5x5=25) for all of the tickets. Even though you now have 5 people in the group, you still only have to pay $5 for each ticket.

This is an example of a constant rate of change.
8 0
4 years ago
Read 2 more answers
CALCULUS EXPERT WANTED. Can someone solve this or at least try to explain to me the fundamental theorem of calculus (FTC).
Amanda [17]

a. By the FTC,

\displaystyle\frac{\mathrm d}{\mathrm dx}\int_1^{\cos x}(t+\sqrt t)\,\mathrm dt=(\cos x+\sqrt{\cos x})\dfrac{\mathrm d}{\mathrm dx}\cos x=-\sin x(\cos x+\sqrt{\cos x})

b. We can either evaluate the integral directly, or take the integral of the previous result. With the first method, we get

\displaystyle\int_1^{\cos x}(t+\sqrt t)\,\mathrm dt=\dfrac{t^2}2+\dfrac{2t^{3/2}}3\bigg|_{t=1}^{t=\cos x}=\left(\dfrac{\cos^2x}2+\dfrac{2(\cos x)^{3/2}}3\right)-\left(\dfrac12+\dfrac23\right)

=\dfrac{\cos^2x}2+\dfrac{2\sqrt{\cos^3x}}3-\dfrac76

c. The derivative of the previous result is

\dfrac{2\cos x(-\sin x)}2+\dfrac{2\cdot\frac32(\cos x)^{1/2}(-\sin x)}3=-\sin x\cos x-\sin x\sqrt{\cos x}

which is the same as the answer given in part (a), so ...

d. ... yes

4 0
3 years ago
Equivalent expression 6(a+b)
Bingel [31]

Answer:

6a + 6b

Step-by-step explanation:

7 0
3 years ago
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