0.600
In a regression analysis, if sse = 200 and ssr = 300, then the coefficient of determination is: <u>0.600</u>
<u></u>
1. You have that the data set having SSR=300 and SSE=200
2. Therefore you have the coefficient of determination is:
r²=SSR/SSTO
SSTO=SSR+SSE
3. Then, when you substitute the values, you obtain:
SSTO=200+300
SSTO=500
r²=300/500
4. So, you have that the result is:
r²=0.6
As a result, as you can see, the solution to the previous exercise is that the coefficient of determination is 0.6
<h3>What exactly is the connection between SST, SSR, and SSE?</h3>
- The difference between SST and SSR is the amount of Y's variability that is still unaccounted for after using the regression model, also known as the sum of squared errors (SSE). Sum of squares of residual can be used to directly calculate SSE.
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The force of a test charge would be doubled if the electric field is doubled.
Answer: Option A
<u>Explanation:</u>
Electric field is the region or range up to which a charge particle will have its influence of electric energy on another charged particles. So the experienced force by the test charge up to a certain range is defined as the electric field of that charged particle.
This means that the electric field strength is inversely proportionate to the test charge and directly proportionate to the force acting on the test charge. As
,

So, force will be product of electric field strength with test charge. Thus,

So, if there is increase in the electric field, then there will be increase in the force of the test charge. Thus, if the electric field is doubled thereby the force of a test charge will also be doubled.
For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as
du=0.2512J
<h3>What is the largest potential energy difference (in Joules) you can find between two orientations?</h3>
Generally, the equation for the initial velocity is mathematically given as
v0=-iAB
Therefore
-2*\pi(0.2)(0.5))
v0=-0.1256J
for 180
theta=0180=-iABcos180
V180=0.1256J
Therefore
du=v180-v0
0.1258-(-0.1256
du=0.2512J
In conclusion, potential energy
du=0.2512J
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The difference between A,B,C,D are that the yields go up a with the carbon dioxide for EF and G the temp goes up but not the carbon dioxide