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Mashutka [201]
3 years ago
14

A point charge is released from rest in a region containing an electric field. The charge will start to move

Physics
1 answer:
kotykmax [81]3 years ago
6 0

Answer:

b) in a direction that makes its potential energy decrease.

Explanation:

  • As the electric field has the direction that would take a positive test charge under its sole influence, the positive test charge, will have an increase in its kinetic energy.
  • Due to the conservation of energy, in absence of non-conservative forces, this increment must be equal and opposite  to the  change in electric potential energy, which will be always negative, independent of the sign of the charge.

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A machine lifts a 44,760 newton crate 2 meters into the air in 10 seconds. How many horsepower does the machine
VladimirAG [237]

Answer:

<u>8952 W</u>

Explanation:

<u>Given</u> :

  • Force = 44,760 Newtons
  • Displacement = 2 meters
  • Time taken = 10 seconds

<u>Equation</u>

  • Power = Work / Time
  • Power = Force x Displacement / Time

<u>Solving</u> :

  • P = 44760 x 2 / 10
  • P = 4476 x 2
  • P = <u>8952 W</u>
7 0
2 years ago
In a regression analysis, if sse = 200 and ssr = 300, then the coefficient of determination is:_________
Nataliya [291]

0.600

In a regression analysis, if sse = 200 and ssr = 300, then the coefficient of determination is: <u>0.600</u>

<u></u>

1. You have that the data set having SSR=300 and SSE=200

2. Therefore you have the coefficient of determination is:

r²=SSR/SSTO

SSTO=SSR+SSE

3. Then, when you substitute the values, you obtain:

SSTO=200+300

SSTO=500

r²=300/500

4. So, you have that the result is:

r²=0.6

As a result, as you can see, the solution to the previous exercise is that the coefficient of determination is 0.6

<h3>What exactly is the connection between SST, SSR, and SSE?</h3>
  • The difference between SST and SSR is the amount of Y's variability that is still unaccounted for after using the regression model, also known as the sum of squared errors (SSE). Sum of squares of residual can be used to directly calculate SSE.

To learn more about regression analysis visit:

brainly.com/question/12213669

#SPJ4

8 0
2 years ago
Select the correct answer.
Nastasia [14]

The force of a test charge would be doubled if the electric field is doubled.

Answer: Option A

<u>Explanation:</u>

Electric field is the region or range up to which a charge particle will have its influence of electric energy on another charged particles. So the experienced force by the test charge up to a certain range is defined as the electric field of that charged particle.

This means that the electric field strength is inversely proportionate to the test charge and directly proportionate to the force acting on the test charge.  As ,

               E=\frac{\text { Force }}{\text { Test charge }}

So, force will be product of electric field strength with test charge.  Thus,

              \text { Force } \propto \text { Test charge and Force } \propto \text { Electric field }

So, if there is increase in the electric field, then there will be increase in the force of the test charge. Thus, if the electric field is doubled thereby the force of a test charge will also be doubled.

4 0
4 years ago
A current loop with radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T. Considering all possible orientations
Orlov [11]

For a current loop with a radius 20 cm and current 2 A is in a uniform magnetic field of 0.5 T, largest potential energy difference is mathematically given as

du=0.2512J

<h3>What is the largest potential energy difference (in Joules) you can find between two orientations?</h3>

Generally, the equation for the initial velocity  is mathematically given as

v0=-iAB

Therefore

-2*\pi(0.2)(0.5))

v0=-0.1256J

for  180

theta=0180=-iABcos180

V180=0.1256J

Therefore

du=v180-v0

0.1258-(-0.1256

du=0.2512J

In conclusion,  potential energy

du=0.2512J

Read more about Energy

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8 0
2 years ago
HELP HELP HELP IM DYING photosynthesis leafs
emmasim [6.3K]
The difference between A,B,C,D are that the yields go up a with the carbon dioxide  for EF and G the temp goes up but not the carbon dioxide
7 0
3 years ago
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