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lawyer [7]
3 years ago
11

If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardl

ess of the order in which each object was plotted. True False
Physics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

True

Explanation:

It Depends on the order in which each object was plotted, if two connected points objects pass through the same set of three points, the shapes created by each point may be different

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4. What happens to the composition of an atom to cause it to become positively or negatively charged?
MakcuM [25]
In an atom, you have three particles: protons, electrons, and neutrons. 

When you add or subtract electrons from an atom, it means that there are either more protons than electrons (positively charged) or there are more electrons than protons (negatively charged).

You cannot add or subtract protons since they are the atomic number, which means the number of protons determines the element. Neutrons have a neutral charge, so they wouldn't affect the charge at all.
8 0
3 years ago
This is a term use to describe an ecological community in which moisture and temperature are high
Yuri [45]

It is described as having a marshy surface where mosses, lichens, berries and low shrubs grow with mucky soil and permafrost underneath. This is a term use to describe an ecological community in which moisture and temperature are high. This is a northern hemisphere habitat with wet soil.

8 0
3 years ago
A 150 kg car hits a wall with 45 N of force, what was its acceleration?​
alisha [4.7K]

Answer:

a = 0.3 m/s²

Explanation:

Given: 45 N, 150 kg

To find: a

Formula: a = \frac{F}{m}

Solution: To find a, divide the force by the weight  

A = F ÷ m

=  45 ÷  150

= 0.3 m/s²

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

4 0
3 years ago
A uniform meter rule of weight 0.9N is suspended horizontally by two vertical loops of thread A and B placed 20cm and 30cm from
Rzqust [24]

The  distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.

<h3>Distance from the center of the meter rule</h3>

The distance from the centre of the rule at which a 2N weight must be suspend from A is calculated as follows;

-----------------------------------------------------------------

  20 A  (30 - x)↓      x         ↓      20 cm  B 30 cm

                       2N              0.9N

Let the center of the meter rule = 50 cm

take moment about the center;

2(30 - x) + 0.9(x)(30 - x) = 0.9(20)

(30 - x)(2 + 0.9x) = 18

60 + 27x - 2x - 0.9x² = 18

60 + 25x - 0.9x² = 18

0.9x² - 25x - 42 = 0

x = 29.3 cm

Thus, the  distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.

Learn more about brainly.com/question/874205 here:

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7 0
2 years ago
Read 2 more answers
When a parachute opens, the air exerts a large drag force on it. This upward force is initially greater than the weight of the s
Pani-rosa [81]

Answer: 1.0052m/s^{2}

Explanation:

Assuming there is only force in the y-component, the total net force F_{y} acting on the parachute and the sky diver is:

F_{y}=F_{D}-W   (1)

Where:

F_{D}=1032N is the drag force acting upwards

W=936N is the weight of the sky diver acting downwards, hence with negative sign

Then:

F_{y}=1032N-936N=96N   (2) This is the total net force excerted on the system parachute-sky diver, and the fact it is positive means is upwards

Now, according Newton's 2nd Law of Motion the force is directly proportional to the mass m and to the acceleration a of a body:

F_{y}=m.a (3)

Where m=95.5kg is the mass of the diver.

Substituting the known values and finding a:

a=\frac{F_{y}}{m} (4)

a=\frac{96N}{95.5kg} (5)

Finally:

a=1.0052m/{s^{2}}\approx 1m/s^{2}  This is the acceleration of the sky diver. Note it has a positive sign, which means its direction is upwards.

6 0
3 years ago
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