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lawyer [7]
3 years ago
11

If two connected points objects pass through the same set of three points, the shapes created by each will be identical, regardl

ess of the order in which each object was plotted. True False
Physics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

True

Explanation:

It Depends on the order in which each object was plotted, if two connected points objects pass through the same set of three points, the shapes created by each point may be different

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Which part of the central nervous system controls reflexes?
larisa86 [58]

Answer:

spinal cord becuse it does all of the reflexes

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A train travels 77 kilometers in 1 hour, and the 66 kilometers in 1 hour. What is the average speed?
Kipish [7]

Average speed = (total distance covered) / (time to cover the distance)

Total distance = (77km + 66km) = 143 kilometers

Time to cover the distance = 2 hours

Average speed = (143 km) / (2 hours) =  71.5 km per hour
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3 years ago
The emt must assume that any unwitnessed water-related incident is accompanied by:________
natta225 [31]

The EMT must assume that any unwitnessed water-related incident is accompanied by potential spinal damage.

<h3>What is spinal damage?</h3>
  • Nerves or the spinal cord in any way damaged at the end of the spinal canal.
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3 0
1 year ago
Use newton's method to find the second and third approximation of a root of
Nina [5.8K]
Please answer this question 

5 0
3 years ago
The aurora is caused when electrons and protons, moving in the earth’s magnetic field of ≈5.0×10−5T, collide with molecules of t
ollegr [7]

Answer:

8.79*10^6 rad/s

Explanation:

To find the frequency of the circular orbit for an electron you use the following expression, for the radius of the trajectory of an electron, that travels trough a constant magnetic field:

r=\frac{mv}{qB}         (1)

r: radius of the trajectory

m: mass of the electron = 9.1*10^-31 kg

v: speed of the electron = 1.0*10^6 m/s

q: charge of the electron = 1.6*10^-19 C

B: magnitude of the magnetic field = 5.0*10^-5 T

You use the fact that the angular frequency in a circular motion is given by:

\omega=\frac{v}{r}

Then, you solve the equation (1) in order to obtain v/r:

\frac{v}{r}=\omega=\frac{qB}{m}

Finally, you replace the values of the parameters:

\omega=\frac{(1.6*10^{-19}C)(5.0*10^{-5}T)}{9.1*10^{-31}kg}\\\\\omega=8.79*10^6\frac{rad}{s}

hence, the angular frequency is 8.79*10^6 rad/s

The frequency is:

f=2\pi \omega=5.5*10^7Hz

5 0
3 years ago
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