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oee [108]
3 years ago
11

A cylindrical tungsten filament 14.0 cmcm long with a diameter of 1.00 mmmm is to be used in a machine for which the temperature

will range from room temperature (20 ∘C∘C) up to 120 ∘C∘C. It will carry a current of 14.0 AA at all temperatures ( Resistivity of tungsten at 20 ∘C∘C is
Physics
1 answer:
Advocard [28]3 years ago
8 0

Answer:

Resistivity ρ=1.12 x 10^-4 Ωm

Explanation:

ρ= RA/l, where R is resistance, A is cross sectional area and l is length

A=πr^2

Note Current is given R is proportion to temperature and inversely proportional to Current R=(20+273)/14*10^-2 =2000Ω

⇒ρ=R*πr^2/l all length in metre.

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A cart travels 4.00 meters east and then4.00 meters north. determine the magnitude ofthe cart’s resultant displacement.
gogolik [260]
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Square root of (4^2 + 4^2) = 4*squareRoot(2)
7 0
3 years ago
What is a saturated solution? In your own words not Google's
SSSSS [86.1K]
A saturated solution is one that cannot dissolve any more of the substance that is mixed into it.
8 0
3 years ago
Two moles of an ideal monatomic gas go through the cycle abc. For the complete cycle, 800 J of heat flows out of the gas. Proces
KiRa [710]

a) Sketches of all possible pv-diagrams for the cycle are attached below

b) The work W_{ac} for the process Ca is : 2462.8  J

<u>Given data :</u>

Amount of heat flowing out = 800 J

Ta = 200 K

Tb = 300 K

R = 800

<u>B) Determine the </u><u>work W </u><u>for the process</u><u> Ca</u><u> </u>

Wₐs = -pdv

       = - [ pVb - pVa ] ---- ( 1 )

note : pVb = nRTb ,  pVa = nRTa

Equation ( 1 ) becomes

= -nR [ Tb - Ta ]

= - 2(8.314 ) [ 300 - 200 ]

= - 1662.87

given that W_{bs} = 0 which is isochonic

dv = 0 ( cyclic process ) = d∅ - dw

∴ 0 = 800 - ( Wₐs  +  W_{ac} )

Therefore : W_{ac} = 800 + 1662.8 = 2462.8  J

Hence we can conclude that the work W for the process Ca = 2462.8  J

Learn more about Pv diagrams : brainly.com/question/25401637

Download pdf
3 0
3 years ago
21. An AC generator has an rms output voltage of 274 V at a frequency of 57.0 Hz.
maks197457 [2]

The answers are as follows;

a) the inductive reactance is 322 ohm

b) The maximum voltage is 387.5 V

c) The rms and maximum currents in the inductor are 1.2 A and 0.85 A.

<h3>What is the reactance?</h3>

The reactance is obtained from;

XL = 2πfL

XL = 2 * 3.14 * 57.0 * 0.900

XL = 322 ohm

The maximum voltage is obtained as;

Vo = Vrms * √2

Vo =  274 V * √2

Vo = 387.5 V

Io = Vo/XL

Io =  387.5 V/ 322 ohm

Io = 1.2 A

Irms = 274 V/322 ohm

Irms = 0.85 A

Learn more about inductive reactance:brainly.com/question/17129912

#SPJ1

4 0
2 years ago
D
Ber [7]

Answer:

D

Explanation:

I think you got it right

3 0
3 years ago
Read 2 more answers
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