Answer:
Explanation:
Wave length of sound from each of the speakers = 340 / 1700 = .2 m = 20 cm
Distance between first speaker and the given point = 4 m.
Distance between second speaker and the given sound
= √ 4² + 2² = √16 +4 = √20 = 4.472 m
Path difference = 4.472 - 4 = .4722 m.
Path difference / wave length = 0.4772 / 0.2 = 2.386
This is a fractional integer which is neither an odd nor an even multiple of half wavelength. Hence this point of neither a perfect constructive nor a perfect destructive interference.
Answer:
0.763 m
Explanation:
Intensity I = power P ÷ area A of exposure (spherical area of propagation)
I = P/A
A = P/I
Power = 10.0 W
Intensity = 1.39 W/m^2
A = 10/1.39 = 7.19 m^2
Area A = 4¶r^2
7.19 = 4 x 3.142 x r^2
7.19 = 12.568r^2
r^2 = 7.19/12.568 = 0.57
r = 0.753 m
Some of the benefits are increased heart muscles, increase in blood flow, and reduced body fat
Answer:
calculate the slope of the line and the slope is equal to the resistance of the circuit m=R
Explanation:
One method for measuring the resistence is to use ohm's law
V = R I
y = mx +b
b=0
m = R
Where we measure various values of voltage and current, with these values we can make a graph of V vs I where we calculate the slope of the line and the slope is equal to the resistance of the circuit
Answer:
a) F1 = 1999.8 N
, F2 = 4545 N
, F3 = 2778 N
, c) the cans do not collapse because the pressure is applied on both sides
Explanation:
Let's use the pressure equation
P = F / A
Suppose we have atmospheric pressure 1.01 10⁵ Pa
Let's calculate the area of the can that is a parallelepiped
Length L = 25 cm
width a = 18 cm
high h = 11 cm
Side area A = h a
A = 11 18
A1 = 198 10⁻⁴ m²
Lid area
A2 = L a
A2 = 25 18
A2 = 450 10⁻⁴ m²
Other side area
A3 = L h
A3 = 25 11
A3 = 275 10⁻⁴ m²
Now let's calculate the force on these sides
Side 1
F1 = P * A1
F1 = 1.01 10⁵ 198 10⁻⁴
F1 = 1999.8 N
Side 2
F2 = P A2
F2 = 1.01 10⁵ 450 10⁻⁴
F2 = 4545 N
Side 3
F3 P A3
F3 = 1.01 10⁵ 275 10⁻⁴
F3 = 2778 N
We see that the force is greater on side 2 which is where the can should collapse
b) To compare the previous forces we must use the concept of density, in general the cans are made of aluminum that has a density of 2700 kg / m3
d = m / V
m = d * V
V = L a h
V = 0.25 0.18 0.11
V = 0.00495 m3
m = 2700 0.00495
m = 13.4 kg
This is the maximum weight, because much of the volume we calculate is air that has a much lower density
W = 13.4 * 9.8
W = 131.3 N
Let's make the comparison by saying the two magnitudes
Side 1
F1 / W = 1999.8 / 131.3
F1 / W = 15.2
Side 2
F2 / W = 4545 / 131.3
F2 / W = 34.6
Side 3
F3 / W = 2778 / 131.3
F3 / W = 21.2
c) the cans do not collapse because the pressure is applied on both sides: outside and inside, so the net force is zero on each side.
