How did the social structure of ancient Rome affect the lives of its people?

A 0.145 kg baseball is thrown horizontally at 15 m/s from a platform, so that it starts at 5.2 m above the ground. How much has

fomenos

7.4J
final kinetic energy
= initial potential energy
= mass x gravitational force x height
= 0.145 x 9.81 x 5.2
= 7.39674 J

6 0

2 years ago

A +15 nC point charge is placed on the x axis at x = 1.5 m, and a -20 nC charge is placed on the y axis at y = -2.0m. What is th

IceJOKER [234]

Answer: $E=75\ N/m$

Explanation:

Given

First charge of $q_1=15\ nC$ is placed at $x=1.5\ m$

Second charge $q_2=-20\ nC$ is placed at $y=-2\ m$

Electric field is given by

$E=\frac{kq}{r^2}$

Electric field due to $q_1$ is away from it

$E_1=\frac{9\times 10^9\times 15\times 10^{-9}}{(1.5)^2}$

$E_1=60\ N/m$

Electric field due to $q_2$

$E_2=\frac{9\times 10^9\times 20\times 10^{-9}}{2^2}$

$E_2=45\ N/m$

Net electric field will be vector addition of two

$\vec{E_{net}}=\vec{E_1}+\vec{E_2}$

$\vec{E_{net}}=-60\hat{i}-45\hat{j}$

Magnitude of Electric field is

$E=\sqrt{60^2+45^2}$

$E=75\ N/m$

8 0

3 years ago

It is noted that a sample of 134La with a half-life of 6.5 minutes has an activity of 2.6 Ci. What was its activity 72 minutes a

stira [4]

Answer:

36//

Explanation:

(½)^t

(½)^72

72/2=36//

5 0

3 years ago

A ball rolls off the top of the roof of a building that is 13 meters tall. Calculate the amount of time it takes for it to hit t

kramer

Answer:

The ball takes $t=1 \cdot 917sec$ to hit the ground.

Explanation:

• The second equation of motion represents the total distances travelled by an object in a time interval of $\Delta t$ with an initial speed of $u$ and acceleration $a$ .

• To find the time, ball takes to hit the ground, use the formula: $s = ut + \frac{1}{2}a{t^2}$

Where, $t$ is time, $u$ is initial velocity, $a$ is acceleration and $s$ is displacement.

• In this case, $a = g = 9 \cdot 8m/se{c^2}$ .

• Placing the value of the given initial velocity, $u=0cm/s$ and displacement, $s = 13m$ in the above formula.

$& \therefore s = ut + \frac{1}{2}g{t^2} \\& \Rightarrow 13 = 0 \cdot t + \frac{1}{2} \times 9 \cdot 8 \times {t^2} \\$

$& \Rightarrow 13 = 4 \cdot 9{t^2} \\& \Rightarrow {t^2} = \frac{{13}}{{4.9}} \\& \Rightarrow t = 1 \cdot 917sec \\\end{align}\]$

• Hence, ball takes $t=1 \cdot 917sec$ to hit the ground.

Learn more about second equation of motion here:

brainly.com/question/19030143

5 0

2 years ago

Which of the following items best embodies the physical property of conductivity?

Sladkaya [172]

C is the correct answer

7 0

2 years ago

Read 2 more answers