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Ivenika [448]
3 years ago
12

A block is sliding down an inclined plane that makes an angle of 65o with the horizontal. If the coefficient of kinetic friction

between the block and plane is 0.17, what is the magnitude of the block’s acceleration down the plane?

Physics
1 answer:
Nezavi [6.7K]3 years ago
4 0

Answer:

8.2 m/s²

Explanation:

m = mass of the block

μ = Coefficient of kinetic friction = 0.17

F_{n} = Normal force on the block by the ramp

f_{k} = kinetic frictional force

Force equation perpendicular to ramp surface is given as

F_{n} = mg Cos65

Kinetic frictional force is given as

f_{k} = \mu F_{n}

f_{k} = \mu mg Cos65

Force equation parallel to ramp surface is given as

mg Sin65 - f_{k} = ma

mg Sin65 - \mu mg Cos65 = ma

g Sin65 - \mu g Cos65 = a

(9.8) Sin65 - (0.17) (9.8) Cos65 = a

a = 8.2 m/s²

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3 years ago
Discuss what in particular makes the light bulb a non-ohmic resistor. Specifically, how does temperature affect resistance? Can
bagirrra123 [75]

Answer:

the loss of energy due to the Joule effect is the cause of the non-ohmic characteristic of the bulb

Explanation:

A resistance is formed of some type of metal, in a light bulb it is Tungsten, which for low current is a resistance that complies with the ohm law.

When the value of the current is increased the shock of the electors creates a Joule effect, which heats the metal, these shocks are due to atomic imperfections of the structure, this heating creates a loss of energy of the system that causes the characteristic to be lost linear between the voltage and the current, since the total energy balance must be preserved.

An approximate measure of the energy that is emitted is given by Stefan's law.

In short, the loss of energy due to the Joule effect is the cause of the non-ohmic characteristic of the bulb

8 0
3 years ago
Suppose that the distance an aircraft travels along a runway before takeoff is given by Upper D equals (5 divided by 3 )t square
Dahasolnce [82]

Answer:

a. Time=25seconds

b.distance=1041.67m

Explanation:

a.The equation for D in terms of m/s is \frac{250}{3}m/s after conversion.

To find when speed reaches 300km/hr=83.33m/s, we find D\prime and solve for t

D=\frac{5}{3}t^2\\D\prime=\frac{5}{3}(2t)=\frac{10}{3}t=\frac{250}{3}\\t=25sec

b. From a, above we already have our t=25seconds as the time it takes before the plane is airborne.

#To find distance travelled in that time , we substitute fort=25 in our distance equation:

D(25)=\frac{5}{3}(25)^2\\=1041.67m

Hence the distance of the plane before it gets airborne is 1041.67m

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c). (10 kWh) x (15 cents/kWh) = $1.50
4 0
3 years ago
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