1. the conductivity of the material
2. temprature differences
3.thickness of the material
4. area of the material
Depending on what way you are trying to use it electrons connect to almost anything just like little balls of magnetics think of it that way. of it being able to just force and charge into any thing.
The simple definition of work is the product of the force applied to the object and the displacement:
W = Fd
W is the work, F is the applied force, and d is the displacement.
Givens:
W = 5.0N-m
F = 25N (the applied force must be at least equal to the weight to lift it)
Plug in the given values and solve for d:
5.0 = 25d
d = 0.20m
Answer: option A. r = 3x+2y
Explanation:
Vector r is plotted on the graph. On x-axis each small division corresponds to 1 unit. Similarly on y-axis, each small division corresponds to one unit.
The vector is the resultant of addition of its x and y components. we would draw perpendicular to the x-axis and y-axis from the head of vector r.
On x-axis,
= +3 units
on y-axis,
= +2 units

Hence, vector r can be written as: r = 3x + 2y . Correct option is A.
Answer:

Explanation:
To calculate the force we need to use this equation

where L is the total length of the wire
So in this case the small element of current is

Because x is the direction of the current flow.
As is said in the problem B is such that
![\vec{B} = B \hat{j} = 0.62\hat{j} [ T]](https://tex.z-dn.net/?f=%20%5Cvec%7BB%7D%20%3D%20B%20%5Chat%7Bj%7D%20%3D%200.62%5Chat%7Bj%7D%20%5B%20T%5D)
so to use the equation above we first calculate the following cross product:

so the force:
So here we use the fact that B=0 in any point of the x axis that is not
, that means that we only need to do the integration between a very short distant behind the point
and a very short distant after that point, meaning:

so is the same as evaluating
at 
that is:



