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julia-pushkina [17]

3 years ago

10

What do high pressure systems actually cause?

2 answers:

Zinaida [17]3 years ago

6 0

A

High-pressure systems<span> are frequently associated with light winds at the surface and subsidence through the lower portion of the troposphere. In general, subsidence will dry out an air mass by adiabatic or compressional heating. Thus, </span>high pressure<span> typically brings clear skies.</span>

erica [24]3 years ago

3 0

Hello! I’m happy to help you.
Believe me, I know how it is when you’re in desperate need.

So really, areas of high and low pressure are caused by ascending and descending air. As air warms, it ascends leading to low pressure at the surface. ... Also the air is descending, which reduces the formation of cloud and leads to light winds and settled weather conditions.

From looking at your options, the answer will be choice A.
I hope this helps answer your question.
If you have absolutely anymore concerns just post them in comments and I’m more than willing to answer. Have a terrific night!

~Brooke❤️

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A high jumper jumps 2.04 m. If the jumper has a mass of 67 kg, what is his gravitational potential energy at the highest point i

Mariulka [41]

Answer: 1339.5 joules

Explanation:

Gravitational potential energy, GPE is the energy possessed by the jumper as he moves against gravity.

Thus, GPE = Mass m x Acceleration due to gravity g x Height h

Since Mass = 67kg

g = 9.8m/s^2

h = 2.04 metres

Thus, GPE = 67kg x 9.8m/s^2 x 2.04m

GPE = 1339.5 joules

Thus, the gravitational potential energy at the highest point is 1339.5 joules

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3 years ago

A jet airliner moving initially at 406 mph (with respect to the ground) to the east moves into a region where the wind is blowin

astraxan [27]

Answer:

966 mph

Explanation:

Using as convention:

- East --> positive x-direction

- North --> Positive y-direction

The x- and y- components of the initial velocity of the jet can be written as

$v_{1x} = 406 mph\\v_{1y} = 0$

While the components of the velocity of the wind are

$v_{2x} = (568)(cos 15^{\circ})=548.6 mph\\v_{2y} = (568)(sin 15^{\circ})=147.0 mph$

So the components of the resultant velocity of the jet are

$v_x = v_{1x}+v_{2x}=406+548.6=954.6 mph\\v_y = v_{1y}+v_{2y}=0+147.0=147.0 mph$

And the new speed is the magnitude of the resultant velocity:

$v=\sqrt{v_x^2+v_y^2}=\sqrt{(954.6)^2+(147.0)^2}=965.8 mph \sim 966 mph$

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3 years ago

If the Earth rotated in the opposite direction, how would that affect the wind? *

Alik [6]

Answer:

The wind would still blow, but it would curve and spin in the opposite direction.

Explanation:

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3 years ago

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An object moves in one dimensional motion with constant acceleration a = 4.2 m/s^2. At time t = 0 s, the object is at x0 = 3.9 m

solong [7]

Answer:

The object will move to Xfinal = 7.5m

Explanation:

By relating the final velocity of the object and its acceleration, I can obtain the time required to reach this velocity point:

Vf= a × t ⇒ t= (7.2 m/s) / (4.2( m/s^2)) = 1,7143 s

With the equation of the total space traveled and the previously determined time I can obtain the end point of the object on the x-axis:

Xfinal= X0 + /1/2) × a × (t^2) = 3.9m + (1/2) × 4.2( m/s^2) × ((1,7143 s) ^2) =

= 3.9m + 3.6m = 7.5m

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4 years ago

Which equation is equivalent to Log (26•35) ?

Nady [450]

Answer:

Log (26) + Log (35)

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