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AlexFokin [52]
3 years ago
13

A 40.0 kg child is in a swing that is attached to ropes 2.00 m long. Find the gravitational potential energy associated with the

child relative to the child’s lowest position under the following conditions:
a. when the ropes are horizontal
b. when the ropes make a 30.0° angle with the vertical
c. at the bottom of the circular arc
Physics
1 answer:
o-na [289]3 years ago
8 0

Answer:

A. As the ropes are horizontal the child has travelled 2m of vertical displacement from his lowest position.

Gpe @ A=mgh=40*9.81*2=784.8J

B. At 30degree vertical angle the vertical displacement from lowest position is given by

2-2cos(30)=2-1.73=0.27m

Gpe @B= 40*9.81*0.27=106 J

C: at the bottom of circular arc it's Gpe is zero relative to lowest position as bottom of arc itself is lowest position.

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A long cylindrical capacitor is made of a central wire of radius a = 2.50 mm surrounded by a conducting shell of radius b = 7.50
asambeis [7]

Answer:

The capacitance per unit length is 5.06\times10^{-11}\ F/m

(b) is correct option.

Explanation:

Given that,

Radius a= 2.50 mm

Radius b=7.50 mm

Dielectric constant = 3.68

Potential difference = 120 V

We need to calculate charge per length for the capacitance

Using formula of charge per length

\lambda=\dfrac{4\pi\epsilon_{0}\Delta V}{2 ln(\dfrac{r_{2}}{r_{1}})}

Put the value into the formula

\lambda=\dfrac{120}{9\times10^{9}\times2 ln(\dfrac{7.50\times10^{-3}}{2.50\times10^{-3}})}

\lambda=6.068\times10^{-9}\ C/m

We know that,

\lambda=\dfrac{Q}{L}

We need to calculate the capacitance per unit length

Using formula of capacitance per unit length

C=\dfrac{\dfrac{Q}{L}}{\Delta V}

C=\dfrac{6.068\times10^{-9}}{120}

C=5.06\times10^{-11}\ F/m

Hence, The capacitance per unit length is 5.06\times10^{-11}\ F/m

7 0
3 years ago
Two cars travel in the same direction along a straight highway, one at a constant speed of 55 mi/h and the other at 60 mi/h.How
Pachacha [2.7K]

Answer:

The distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.

Explanation:

Given;

speed of the faster car, v₁ = 60 mi/h

speed of the slower car, v₂ = 55 mi/h

Let the distance traveled by the faster car when it is 15 mins ahead of the slower car = x miles

\frac{x}{55} - \frac{x}{60}   = \frac{15}{60}

Note: divide 15 mins by 60 to convert to hours for consistency in the units.

\frac{x}{55} - \frac{x}{60}   = \frac{15}{60}\\\\multiple \ through \ by \ 660\\\\12x - 11x = 165\\\\x = 165 \ miles

Therefore, the distance traveled by the faster car when it is 15 mins ahead of the slower car is 165 miles.

4 0
3 years ago
What is the freezing point of radiator fluid that is 50% antifreeze by mass? k f for water is 1.86 ∘ c/m?
densk [106]
Ethylene glycol is termed as the primary ingredients in antifreeze.
The ethylene glycol molecular formula is C₂H₆O₂.
Molar mass of C₂H₆O₂ is = (2×12) +(6×1) + (216) = 62g/mol
Now that antifreeze by mass is 50%, then there is 1kg of ethylene glycol which is present in 1kg of water.
ΔTf = Kf×m
ΔTf = depression in the freezing point.
= freezing point of water freezing point of the solution
= O°c - Tf
= -Tf
Kf = depression in freezing constant of water = 1.86°C/m
M is the molarity of the solution.
=(mass/molar mass) mass of solvent in kg
=1000g/62 (g/mol) /1kg
=16.13m
If we plug the value we get 
-Tf = 1.86 × 16.13 = 30
Tf = -30°c
7 0
3 years ago
Read 2 more answers
Coal and other fossil fuels are considered to be "nonrenewable" sources of energy. How does the use of nonrenewable fuels affect
nignag [31]

Answer: D Although the total energy remains constant, nonrenewable fuels convert chemical energy into forms that are difficult or impossible to use again.

Explanation:

The first law of thermodynamics says that energy can neither be created nor destroyed; energy can only be transferred or changed from one form to another.

7 0
3 years ago
Which component measures the potential difference across a branch in a circuit? A. switch B. resistor C. ammeter D. voltmeter
NNADVOKAT [17]

Answer:

Voltmeter

Explanation:

7 0
3 years ago
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