Imagine that someone pushes one marble toward a motionless marble. Would there still be action-reaction forces involved in the c
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Answer:
Therefore energy is stored in the 1.0 mF capacitor is 5.56×10⁻⁹ J
Explanation:
Series capacitor: The ending point of a capacitor is the starting point of other capacitor.
If C₁ and C₂ are connected in series then the equivalent capacitance is C.
where
Given that,
C₁ = 1.0 mF=1.0×10⁻³F and C₂ = 0.50mF=0.50×10⁻³F
If C is equivalent capacitance.
Then
mF
Again given that the system is connected to a 100-v battery.
We know that
q=Cv
q= charge
C= capacitor
v= potential difference
Therefore
The electrical potential energy stored in a capacitor can be expressed
q= charge
c=capacitance of a capacitor
Therefore energy is stored in the 1.0 mF capacitor is
J