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Rama09 [41]
3 years ago
12

Answer pls . ......​

Physics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

yeah its distance

Explanation:

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How long would it take for a rock falling 97.2 m/s to reach the ground from 100 meters
mote1985 [20]

Answer;

velocity(v) = 97.2 m/s ,

distance (S) = 100 m

determine time(t) = ?

  We know that,

               distance (S) = velocity(v) × time(t)

           So,      time (t) = distance ÷ velocity

                                   = 100 ÷ 97.2

                              <em>   t = 1.02 sec.</em>

<em>I hope this will help you.</em>

5 0
4 years ago
Plssss help Do you guys have any other more interesting, funny or creative ideas of incline problems than something sliding down
VashaNatasha [74]
U can always just do the classic roller coaster going up an incline and create some sort of story from that.
8 0
3 years ago
A ball swings in a horizontal circle. If the radius and the frequency are both doubled, by what factor does the tension in the s
kherson [118]

Answer:

The tension increases by a factor of 8

Explanation:

We know that the tension, T in the string equals the centripetal force on the ball. So

T = mrω² = mr(2πf)² = 4mrπ²f² where m = mass of ball, r = radius of circle and f = frequency of rotation

If the radius and frequency are doubled, then r = 2r and f = 2f. So, the new tension is T' = 4mr'π²f'² = 4m(2r)π²(2f)² = 4 × 2 × 4mrπ²f² = 8T  

Since T' = 8T,

So T'/T = 8.

So the tension increases by a factor of 8

4 0
3 years ago
An egg is thrown nearly vertically upward from a point near the cornice of a tall building. The egg just misses the cornice on t
diamong [38]

Answer:

1. 18.5m/s

2. 17.5 m

3. 0 at its highest point

4. Direction is downwards

Explanation:

1. This egg is thrown vertically from a height

Yo = 0. This egg then falls to the point y = -30.0 at t = 5seconds

Y-Yo = V0t - 1/2gt²

-30-0 = V0(5)-1/2(9.8)(5²)

-30 = 5v0 - 4.9x25

-30 = 5V0 - 122.5

-30+122.4 = 5v0

V0 = 92.5/5

= 18.5m/s

<em><u>this </u></em><em><u>is </u></em><em><u>the </u></em><em><u>initial</u></em><em><u> </u></em><em><u>speed</u></em><em><u> of</u></em><em><u> the</u></em><em><u> </u></em><em><u>egg</u></em>

2. When the egg is at a maximum height it would have a velocity equal to 0

V² = V0² - 2*g*y

V = 0, V0 = 18.5, g = 9.8

0 = 18.5²-2x9.8*y

342.25-19.6y = 0

342.25 = 19.6y

Divide through by 19.6

Y = 342.25/19.6

Y = 17.5m

<em><u>this value is how high it rises above starting point</u></em>

3.

The magnitude of velocity is = 0 at its highest point

4.

This egg falls under gravity. Therefore the acceleration due to gravity has a constant magnitude and direction. Magnitude = 9.8m/s and it's direction is downwards.

5. Please check attachment for graph

6 0
3 years ago
1. A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts
Snezhnost [94]

Answer:

397 j

Explanation:

Because 5.0kg yuh

3 0
2 years ago
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