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3 years ago

Leftover planetesimals that formed in the region of the solar system now occupied by the jovian planets are called

Physics

1 answer:

rewona [7]3 years ago

7 0

Answer:

Comets

Explanation:

Comets are planetary celestial bodies consisting of ice and dust, sometimes rocky particles formed in the region of the solar system. Long-period comets propagate towards the Sun by gravitational perturbations caused by passing stars. Some comets usually hyberbolic comets, move through the inner Solar System prior to entering the interstellar region. Short period comet lies beyond the orbit of the Neptune.

The Jovian planets include Jupiter, Saturn, Uranus, and Neptune.

Therefore, leftovers of comets (planetesimal bodies) formed in the region of the solar system that are now occupied by the Jovian planets is due to the dusty particles associated with the comets.

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¿Por qué se considera que la física parte de las ciencias naturales? dar ejemplos.

vova2212 [387]

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3 years ago

How could the man in the image better improve his posture?

Nadusha1986 [10]

Answer:

Explanation:

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3 years ago

Read 2 more answers

Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. An

Vikentia [17]

Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.

Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.

<h3>What is the relation between the distance in parsecs and the parallax?</h3>

Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.
Then, the equation connecting parallax and the distance in parsec can be written as,

$d=\frac{1}{P}$

We can say that,

$dP=constant.\\thus,\\d_1P_1=d_2P_2$

<h3>How to solve the problem?</h3>

We have given that,

$d_1=2.6 parsecs.\\P_1=0.379arcseconds.\\P_2=0.042 arcseconds.\\d_2=?$

Thus, we can find the distance in parsecs as,

$d_2=\frac{d_1P_1}{P_2} =23.46 parsecs$

Thus, we can conclude that, the distance in parsecs will be, 23.46.

Learn more about the relation connecting distance in parsecs and the parallax here: brainly.com/question/28044776

#SPJ4

6 0

1 year ago

The Earth can be approximated as a sphere of uniform density, rotating on its axis once a day. The mass of the Earth is 5.97×102

svetlana [45]

Answer:

I = 97.2 10³⁶ kg m²

Explanation:

The moment of inertia of a body the expression of inertia in the rotational movement and is described by the expression

I = ∫ r² dm

In this problem we are told to use the moment of inertia of a uniform sphere, the expression of this moment of inertia is

I = 2/5 M r²

where m is the mass of the earth and r is the radius of the earth.

Let's calculate

I = 2/5 5.97 10²⁴ (6.38 10⁶)²

I = 97.2 10³⁶ kg m²

3 0

3 years ago

Calculate the average speed of a complete round trip in which the outgoing 300 km is covered at 93 km/h , followed by a 1.0-h lu

madreJ [45]

Answer : 63 km/h

Explanation :

Outgoing distance = 300 km.

Outgoing speed = 93 km/h.

Break time = 1 h

Return distance = 300 km

Return speed = 56 km/h

Outgoing time = outgoing distance / outgoing speed

Outgoing time = 300 km / 93 km/h = 3.225806451612 h

Return time = return distance / return speed

Return time = 300 km / 56 km/h = 5.357142867142 h

Total distance =. Outgoing distance + return distance travelled

Total distance = 300 km + 300 km = 600 km

Total time = outgoing time + break time + return time

Total time = 3.225806451612 h + 1 h+ 5. 357142867142 h = 9.582949308754 h

Average speed = total distance / total time

Average speed = 600 km / 9.582949308754 h

Average speed = 62.61120462042 km/h = 63 km/h

3 0

3 years ago