The answer to which type of bond shows two or more atoms baring electrons is B. Covalent
<h2>
Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s</h2>
Explanation:
In horizontal direction there is acceleration or deceleration for a ball tossed upward at an initial angle of 43° off the ground.
So the horizontal component of velocity always remains the same.
Horizontal component of velocity is the cosine component of velocity.
Initial velocity, u = 10 m/s
Angle, θ = 43°
Horizontal component of velocity = u cosθ
Horizontal component of velocity = 10 cos43
Horizontal component of velocity = 7.31 m/s
Since the horizontal velocity is unaffected, we have
Component of the velocity of the ball in the horizontal direction just before the ball hits the ground = 7.31 m/s
The rubber protects him from being electrocuted by the flow of current going through the plug.
Hope this helped!!
Answer:
0.2932 rad/s
Explanation:
r = Radius = 2 m
= Initial angular momentum = 
= Initial angular velocity = 14 rev/min
= Final angular momentum
= Final angular velocity
Here the angular momentum of the system is conserved

The final angular velocity is 0.2932 rad/s
Elements of Group 17 are halogens.
Fluorine, Chlorine, Bromine, Iodine, Astatine