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Inessa05 [86]
3 years ago
13

How many significant figures are in the following measurements ?

Physics
2 answers:
Orlov [11]3 years ago
5 0
The number of significant figures are counted by,
non-zeros are significant
Zeros in between non-zeros are significant.
Zeros after the decimal and non zeros are significant.

a. 300000000m/s  = 1 significant figure
<span>b. 3.00x10(8th power) = 3 significant figures</span>
<span>c.25.030*c = 4 significant figures</span>
<span>d. 0.006070 *c = 5 significant figures</span>
<span>e. 1.004 J = 4 significant figures</span>
<span>f. 1.30520 MHz =5 significant figures</span>
kifflom [539]3 years ago
4 0
The number of significant figures are based on the rules:<span>non-zeros are significant  Zeros in between non-zeros are also significant. Trailing zeros are considered not significant. Zeros after the decimal and non zeros are significant.</span>

a. 1
b. 3
c. 5
d. 4
e. 4
f. 6
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9 cm.

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27 = \frac{1}{2}K((21-L^{2})-(15-L^{2}))

45 = \frac{1}{2}K((27-L^{2})-(21-L^{2}))

Dividing both the equation will get,

\frac{3}{5}=\frac{(21-L)^{2}-(15-L)^{2}}{(27-L)^{2}-(21-L)^{2}}\\5((21-L)^{2}-(15-L)^{2})=3((27-L)^{2}-(21-L)^{2})\\3(729 - 54L + L^{2}- 441 + 42L - L^{2} ) = 5(441 - 42L + L^{2} - 225 + 30L - L^{2} )\\3(288 - 12L) = 5(216 - 12L)\\24L = 216\\L = 9 cm

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3 years ago
What causes atoms to bond together<br> ?!?
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electrostatic attraction

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Answer:

I = (1.80 × 10⁻¹⁰) A

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4π × 10⁻⁷ × I = 1.0 × 10⁻¹⁵ × 2π × 0.036

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3 0
3 years ago
There is a moon orbiting an Earth-like planet. The mass of the moon is 9.58 × 1022 kg, the center-to-center separation of the pl
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Answer:

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