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3 years ago

How many significant figures are in the following measurements ?

2 answers:

5 0

The number of significant figures are counted by,
non-zeros are significant
Zeros in between non-zeros are significant.
Zeros after the decimal and non zeros are significant.

a. 300000000m/s = 1 significant figure
b. 3.00x10(8th power) = 3 significant figures
c.25.030*c = 4 significant figures
d. 0.006070 *c = 5 significant figures
e. 1.004 J = 4 significant figures
f. 1.30520 MHz =5 significant figures

kifflom [539]3 years ago

4 0

The number of significant figures are based on the rules:non-zeros are significant Zeros in between non-zeros are also significant. Trailing zeros are considered not significant. Zeros after the decimal and non zeros are significant.

a. 1
b. 3
c. 5
d. 4
e. 4
f. 6

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Given that,

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A rotating paddle wheel is inserted in a closed pot of water. The stirring action of the paddle wheel heats the water. During th

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Answer:

the final energy of the system is 35.5 kJ.

Explanation:

Given;

initial energy of the system, E₁ = 10 kJ

heat transferred to the system, q₁ 30 kJ

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heat gained by the system, Q = q₁ - q₂ = 30 kJ - 5kJ = 25 kJ

work done on the system, W = 500 J = 0.5 kJ

Apply first law of thermodynamic,

ΔU = Q + W

where;

ΔU is change in internal energy

Q is the heat gained by the system

W is work done on the system

ΔU = 25kJ + 0.5 kJ

ΔU = 25.5 kJ

The final energy of the system is calculated as;

E₂ = E₁ + ΔU

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2 years ago

A car traveling at 27.4 m/s hits a bridge abutment. A passenger in the car, who has a mass of 65.0 kg, moves forward a distance

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Answer:

$F=43570.9N$

Explanation:

We can calculate the acceleration experimented by the passenger using the formula $v_f^2=v_i^2+2ad$ , taking the initial direction of movement as the positive direction and considering it comes to a rest:

$a=\frac{v_f^2-v_i^2}{2d}=\frac{-v_i^2}{2d}$

Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:

$F=ma=\frac{-mv_i^2}{2d}$

Which for our values is:

$F=\frac{-(65kg)(27.4m/s)^2}{2(0.56m)}=43570.9N$

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