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2 years ago

How many significant figures are in the following measurements ?

2 answers:

5 0

The number of significant figures are counted by,
non-zeros are significant
Zeros in between non-zeros are significant.
Zeros after the decimal and non zeros are significant.

a. 300000000m/s = 1 significant figure
b. 3.00x10(8th power) = 3 significant figures
c.25.030*c = 4 significant figures
d. 0.006070 *c = 5 significant figures
e. 1.004 J = 4 significant figures
f. 1.30520 MHz =5 significant figures

kifflom [539]2 years ago

4 0

The number of significant figures are based on the rules:non-zeros are significant Zeros in between non-zeros are also significant. Trailing zeros are considered not significant. Zeros after the decimal and non zeros are significant.

a. 1
b. 3
c. 5
d. 4
e. 4
f. 6

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What is the name of the process that is responsible for the formation of elements heavier than hydrogen? A) fusion B) fission C)

gladu [14]

Answer:

A) Fusion

Explanation:

Fusions of atoms heavier than hydrogen like helium takes place in the core of the star, at the core the temperature and density of gases is the greatest .

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How much heat is released when 6.00 grams of ammonia and 5.00 grams of oxygen?

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11 grams were released.think it help

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2 years ago

I need help finding the answer

miss Akunina [59]

Speed = (distance) / (time)

Speed = (2.3 m) / (3 sec)

Speed = (2.3/3) (m/s)

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2 years ago

At a meeting of physics teacher in Montana, the teachers were asked to calculate where a flour sack would land if dropped from a

Harlamova29_29 [7]

At a distance of 469.2 m from the original point below the airplane.

Explanation:

First of all, we have to calculate the time it takes for the sack to reach the ground.

To do so, we just analyze its vertical motion, which is a free-fall motion, so we can use the suvat equation:

$s=ut+\frac{1}{2}at^2$

where, taking downward as positive direction:

s = 300 m is the vertical displacement

u = 0 is the initial vertical velocity

t is the time

$a=g=9.8 m/s^2$ is the acceleration of gravity

Solving for t, we find the it takes for the sack to reach the ground:

$t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(300)}{9.8}}=7.82 s$

Now we analyze the horizontal motion. The horizontal velocity of the pack is constant (since there are no forces along the horizontal direction) and equal to the initial speed of the airplane, so:

$v_x = 60 m/s$

We also know the total time of flight,

t = 7.82 s

Therefore, we can find the horizontal distance travelled by the sack:

$d=v_x t = (60)(7.82)=469.2 m$

So, the sack will land 469.2 m from the original point below the airplane.

Learn more about free fall and projectile motion:

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2 years ago

What total mass must be converted into energy

Eduardwww [97]

This question apparently wants you to get comfortable
with E = m c² . But I must say, this question is a lame
way to do it.

c = 3 x 10⁸ m/s
E = m c²

 1.03 x 10⁻¹³ joule = (m) (3 x 10⁸ m/s)²

Divide each side by (3 x 10⁸ m/s)²:

 Mass = (1.03 x 10⁻¹³ joule) / (9 x 10¹⁶ m²/s²)

 = (1.03 / 9) x (10⁻¹³ ⁻ ¹⁶) (kg)

 = 1.144 x 10⁻³⁰ kg . (choice-1)

This is roughly the mass of (1 and 1/4) electrons, so it seems
that it could never happen in nature. The question is just an
exercise in arithmetic, and not a particularly interesting one.
______________________________________

Something like this could have been much more impressive:

The Braidwood Nuclear Power Generating Station in northeastern
Ilinois USA serves Chicago and northern Illinois with electricity.
The station has two pressurized water reactors, which can generate
a net total of 2,242 megawatts at full capacity, making it the largest
nuclear plant in the state.
If the Braidwood plant were able to completely convert mass
to energy, how much mass would it need to convert in order
to provide the total electrical energy that it generates in a year,
operating at full capacity ?

Energy = (2,242 x 10⁶ joule/sec) x (86,400 sec/day) x (365 da/yr)

 = (2,242 x 10⁶ x 86,400 x 365) joules

 = 7.0704 x 10¹⁶ joules .

How much converted mass is that ?

 E = m c²

Divide each side by c² : Mass = E / c² .
c = 3 x 10⁸ m/s

 Mass = (7.0704 x 10¹⁶ joules) / (9 x 10¹⁶ m²/s²)

 = 0.786 kilogram ! ! !

THAT should impress us ! If I've done the arithmetic correctly,
then roughly (1 pound 11.7 ounces) of mass, if completely
converted to energy, would provide all the energy generated
by the largest nuclear power plant in Illinois, operating at max
capacity for a year !

7 0

2 years ago

Read 2 more answers