By conservation of momentum, we will find that the mass is 4.97 kg.
So in the original system, we have two objects, the bouquet of flowers of mass M that is not moving and Yvonne, which has a mass of 63 kg and a speed of 10.8 m/s.
Then the total momentum of this system is:
P = (63kg)*(10.8m/s) + M*(0 m/s) = 680.4 kg*m/s.
Remember the conservation of momentum, thus, the final momentum must be equal to the above one.
In the final situation, Yvonne and the bouquet move together with a speed of 10.01 m/s,
Then the final momentum is:
P' = (63kg + M)*(10.01 m/s)
And that must be equal to the initial momentum, then we have the equation:
(63kg + M)*(10.01 m/s) = 680.4 kg*m/s.
630.63kg*m/s + M*10.01 m/s = 680.4 kg*m/s.
M*10.01 m/s = 680.4 kg*m/s - 630.63kg*m/s = 49.77 kg*m/s
M = (49.77 kg*m/s)/(10.01 m/s) = 4.97 kg
So the mass of the bouquet is 4.97 kg
If you want to learn more about momentum, you can read:
brainly.com/question/19636349
