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4 years ago

The first artificial satellite to be launched into space was called _____________.

Physics

2 answers:

vodomira [7]4 years ago

8 0

The first artificial Satallite to be lunch into space was called Sputnik I

Gnom [1K]4 years ago

4 0

The first artificial satellite to be launched was called Sputnik I

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S27253129 ,,, message me please, I can't ask you my homework question in the comments :c

Serjik [45]

What’s the problem what do u need help on

7 0

3 years ago

A student finds an unlabeled bottle of liquid under

s344n2d4d5 [400]

Answer:

C. Adding some of the unknown liquid to red litmus paper.

Explanation:

Since the student doesn't know what the liquid is, it is not safe to experiment with it by boiling, cooling, or adding water to it. The safest option would be to add a small bit of the liquid to the litmus paper, which will identify the liquid as neutral, basic, or acidic.

6 0

4 years ago

Read 2 more answers

Suppose the moon were held in its orbit not by gravity but by the tension in a massless cable. You are given that the period of

Ksenya-84 [330]

Answer:

Tension in the cable = 200.655 × 10^(18) N

Explanation:

The tension in the cable will be the force on the string which is caused by when it holds against the centripetal acceleration.

Now, the formula for centripetal acceleration is given by;

a = v²/R

Now, let's find the velocity.

The circumference is 2πR

We are given that R = 3.85 x 10^(8) m

So, Circumference = 2 × π × 3.85 x 10^(8) = 24.19 × 10^(8) m

We are told the period of the moon orbit is 27.3 days

Distance travelled per day = Circumference/ period

Distance travelled per day = (24.19 × 10^(8))/27.3 = 88608058.608 m/day

Now, a day has 24 hours = 24 × 60 × 60 = 86400 seconds

Thus,

Distance travelled per seconds =

88608058.608/86400 = 1025.556 m/sec

So, from a_c = v²/r,

a_c = 1025.556²/3.85x10^8

a_c = 0.00273 m/s²

Now, Force = Mass x Acceleration = ma

We are given mass = 7.35 x 10^(22) kg

Plugging in the relevant values, we have;

F = 0.00273 x 7.35 x 10^(22)

F = 200.655 × 10^(18) N

5 0

3 years ago

If you know how much radioactive material the organism had to begin with, explain how you could use half-life to determine its a

TiliK225 [7]

Answer: We can calculate it with the radioactive half life equation

Explanation:

If we already know the initial amount of radioactive material and its half life, we can leave that material for a specific known time and then measure how much of the material is left (since it follows the radioactive deacay) and use the results in the following formula:

$A=A_{o}.2^{\frac{-t}{h}}$

Where:

$A$ is the final amount of the material

$A_{o}$ is the initial amount of the material

$t$ is the time elapsed

$h$ is the half life of the radioactive compound

5 0

3 years ago

Like the moon's orbit, Earth's orbit is not a perfect circle, but an oval How do you think this might affect Earth's tides?

ExtremeBDS [4]

During the parts in the orbit where the moon is farthest away from the earth the tides will be low. Whereas during the parts where the moon is closer to the earth the tides will be higher.

Good Luck!
Please correct me if i'm wrong

8 0

3 years ago