When a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
From Newton's third equation of motion,
v^2 = u^2 + 2gh
where,
h is the height of the object or body from ground
u is the initial velocity of the body or object
v is the final velocity of the body or object
g is the acceleration due to gravity
Now, as we know that
Flowerpot is at rest. So, u = 0
g = 9.81m/s^2
h = 36.5m
By substituting all the values, we get
v^2 = 2 × 9.81 × 36.5
= 716.13
v = 26.7m/s
Thus, we concluded that when a flowerpot falls from a window sill 36.5 m
above the sidewalk, then the velocity of the flowerpot is 26.7 m/s.
learn more about Newton's equation of law of motion:
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Answer:
Use a lighter string of the same length, under the same tension.
Stretch the string tighter to increase the tension
Explanation:
The wave speed depends on propertices of the medium, not on how you generate the wave. For a string
Increasing the tension or decreasing the linear density (lighter string) will increase the wave speed.
Answer:
Explanation:
The angular speed is given by:
Here v is the linear speed and r is the radius of the circular motion. The height of the tower is equal to the radius of the circular motion of the top of the tower, since is rotating about its base. We need to convert the given linear speed to 
:
Now, we calculate the angular speed:
