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SOVA2 [1]
4 years ago
9

Which articulations allow for greatest range of motion?

Physics
1 answer:
jeka57 [31]4 years ago
7 0
Ball and Socket joints allow for the greatest range of motion.
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Jack (mass 52.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. he collides with jill (mass 49.0 k
dybincka [34]
We must write down laws of conservation of momenta and energy. 
For the law of conservation of momenta will we will use two axes. One will be x-axis that will correspond to the east, and the other one will be y-axis corresponding to the north. Jack will be marked as 1 and Jill will be marked as 2.
Law of conservation of energy:
\frac{m_1v_1^2}{2}=\frac{m_1v'_1^2}{2}+ \frac{m_2v_2^2}{2}\\
m_2v_2^2=m_1v_1^2-m_1v_1'^2\\
v_2=\sqrt{\frac{m_1v_1^2-m_1v_1'^2}{m_2}
This will give us Jill's velocity after the colision.
v_2=6.43\frac{m}{s}
Law of conservation of momenta:
x: m_1v_1=m_1v_1'cos(34)+m_2v_2cos(\theta)\\
y: 0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\
We will use the second equation to get the angle at which the Jill is traveling:
0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\
m_2v_2sin(\theta)=m_1v_1'sin(34)\\
sin(\theta)=\frac{m_1v_1'sin(34)}{m_2v_2}\\
\theta=sin^{-1}(\frac{m_1v_1'sin(34)}{m_2v_2})
When we plug all the number we get:
\theta=27.45^\circ
Please note that this is the angle below the x-axis.

6 0
3 years ago
Hai xe chuyển động trên cùng một đoạn đường , khi xe (1) ở A thì xe (2) ở B phía trước với AB=5km . Xe (1) đuổi theo xe (2) . Tạ
12345 [234]

Answer:

b

Explanation:

because it shows you it

4 0
3 years ago
A wave changing shape when passing through an opening is an example of what?
igomit [66]
It is diffraction !!
7 0
4 years ago
The purpose of a cell (battery) is to: Question 2 options: store chemical energy and transfer it to thermal energy when a circui
xz_007 [3.2K]

Answer:

Store chemical energy and transfer it to electrical energy when a circuit is connected.

Explanation:

A battery (single cell) is a container made of one cell that can produce a particular amount of electrical energy when needed.

It works by converting chemical energy to electric energy which is then used as a power source.

It stores up chemical energy and when connected to an external circuit, it provides electrical energy (through the flow of electrical current) to the circuit.

A battery is usually made up of a positive electrode and a negative electrode.

6 0
3 years ago
A rod 14.0 cm long is uniformly charged and has a total charge of -22.0 μC. Determine the magnitude and direction of the net ele
lesya692 [45]

Explanation:

It is given that,

Length of the rod, l = 14 cm = 0.14 m

Charge on the rod, q=-22\ \mu C=-22\times 10^{-6}\ C

We need to find the magnitude and direction of the net electric field produced by the charged rod at a point 36.0 cm to the right of its center along the axis of the rod, z = 36 cm = 0.36 m

Electric field at the axis of the rod is given by :

E=\dfrac{\lambda}{2\pi \epsilon_o z}

Where

\lambda is the linear charge density of the rod,

\lambda=\dfrac{q}{l}=\dfrac{-22\times 10^{-6}\ C}{0.14\ m}=-0.00015\ C/m

E=\dfrac{-0.00015}{2\pi\times 8.85\times 10^{-12}\times 0.36}

E = -7493170.57 N/C

or

E=-7.49\times 10^6\ N/C

Negative sign shows that the electric field is acting in inwards direction. Hence, this is the required solution.

4 0
3 years ago
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