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Aloiza [94]
3 years ago
15

Two charged particles are separated by 10 cm. suppose the charge on each particle is doubled. By what factor does the electric f

orce between the particles change?
Physics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

The electric force increases by a factor of 4.

Explanation:

The electric force between two charges q_1 and q_2 separated a distance <em>d</em> can be calculated using Coulomb's Law:

F=\frac{kq_1q_2}{d^2}

where k=9\times10^9Nm^2/C^2 is the Coulomb constant.

If the value of each charge is doubled, then we will have a force between them which is:

F'=\frac{k(2q_1)(2q_2)}{d^2}=4\frac{kq_1q_2}{d^2}=4F

So the new force is 4 times larger than the original force.

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A potter spins his wheel at 0.98 rev/s. The wheel has a mass of 4.2 kg and a radius of 0.35 m. He drops a chunk of clay of 2.9 k
Bad White [126]

Answer:

v_{f,w} = 1.791\,\frac{m}{s}, v_{f,c} = 0.972\,\frac{m}{s}

Explanation:

The situation can be modelled by applying the Principle of Angular Momentum Conservation:

I_{w} \cdot \omega_{o} = (I_{w} + I_{c})\cdot \omega_{f}

The final angular speed is:

\omega_{f} = \frac{I_{w}}{I_{w}+I_{c}}\cdot \omega_{o}

\omega_{f} = \left(\frac{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} }{\frac{1}{2}\cdot (4.2\,kg)\cdot (0.35\,m)^{2} + \frac{1}{2}\cdot (2.9\,kg)\cdot (0.19\,m)^{2}}\right)\cdot (0.98\,\frac{rev}{s} )\cdot \left(\frac{2\pi\,rad}{1\,rev}  \right)

\omega_{f} \approx 5.116\,\frac{rad}{s}

The tangential velocities of the wheel and the clay are, respectively:

v_{f, w} = (0.35\,m)\cdot (5.116\,\frac{rad}{s} )

v_{f,w} = 1.791\,\frac{m}{s}

v_{f, c} = (0.19\,m) \cdot (5.116\,\frac{rad}{s} )

v_{f,c} = 0.972\,\frac{m}{s}

5 0
3 years ago
based on how the book describes a heat pump in sec 16.3 how does a heat pump prove law of conservation of energy
sattari [20]
The law of conservation of energy states that: "energy cannot be created nor destroyed. It can only be transformed from one form to the other". A heat pump transfers heat from a colder area to a warmer area. As the conservation of energy goes, the energy that comes in, must equal the energy that comes out. Although no machine is 100% efficient, the missing energy is supplied by an external energy source, such as electricity.
4 0
4 years ago
Two gratings A and B have slit separations dA and dB, respectively. They are used with the same light and the same observation s
77julia77 [94]

Answer:

a) dB / dA = 2 ,

b) Network B     Network A

        2                         1

        4                         2

        6                         3

Explanation:

a) The expression for grating diffraction is

         d sin θ = m λ

where d the distance between two slits, λ the wavelength and m an integer that represents the diffraction range

In this exercise we are told that the two spectra are in the same position, let's write the expression for each network

Network A

m = 1

         sin θ = 1 λ / dA

Network B

m = 2

        sin θ = 2 λ / dB

they ask us for the relationship between the distances, we match the equations

            λ / dA) = 2 λ / dB

            dB / dA = 2

         

b) let's write the equation of the networks

         sin θ = m_A  λ / dA

         sin θ = m_B  λ / dB

we equalize

           m_A  λ/ dA = m_B  λ / dB

we use that

          dB / dA = 2

           m_A 2 = m_B

therefore the overlapping orders are

Network B     Network A

   2                         1

   4                         2

    6                       3

4 0
3 years ago
If my mass is 196 lbm and I tackle one of my teammates - while decelerating from a velocity of 6.7 m/s to 0 m/s in 0.5 s, how mu
Olin [163]

Answer:

the force acting on the team mate is 1.19 kN.

Explanation:

given,

mass = 196 lbm

while tackling, the deceleration is from velocity 6.7 m/s to 0 m/s

time taken for deceleration = 0.5 sec        

F = mass × acceleration

acceleration = \dfrac{0-6.7}{0.5}              

                     = -13.4 m/s²                            

1 lbs  = 0.453 kg                      

196 lbs = 196 × 0.453  = 88.79 kg

F = 88.79 × 13.4                              

F = 1189.786 N = 1.19 kN                      

hence, the force acting on the team mate is 1.19 kN.

8 0
3 years ago
If the magnification produced by a lens has a negative value, the image will be
drek231 [11]

Answer:

I think it's B, not quite sure tho.

8 0
3 years ago
Read 2 more answers
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