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4 years ago

If a 2.00kg ball is thrown straight upward and its maximum height is 25.51. what is the value of KE?

Physics

1 answer:

9966 [12]4 years ago

6 0

Answer:

Check below for answers and explanations.

At the maximum height, KE = 0 J

As the object returns, KE = PE = 500J

Explanation:

At the maximum height, the object momentarily stops, which means that the velocity at the maximum height is zero, i.e. v = 0

Since Kinetic Energy is give by:

KE = 0.5 mv^2

KE = 0.5 * 2 * 0

KE = 0 ( at Max height)

However at the peak, the PE = mgh

PE = 2 *9.8 * 25.51

PE = 500 J

As the object returns back to the ground, the Potential Energy is transformed to kinetic energy, which means that, KE = PE = 500J

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bija089 [108]

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3 years ago

A .025 kg bullet is moving at 350 m/s when it hits and then passes through a 7 kg block of wood. After the bullet passes through

slamgirl [31]

Answer:

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Explanation:

Given that mass of bullet = $m_{b} = 0.025kg$

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3 years ago

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Answer:

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Explanation:

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3 years ago

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3 years ago

Suppose that a steel bridge, 1000 m long, were built without any expansion joints. Suppose that only one end of the bridge was h

Stels [109]

Answer:

The difference in the length of the bridge is 0.42 m.

Explanation:

Given that,

Length = 1000 m

Winter temperature = 0°C

Summer temperature = 40°C

Coefficient of thermal expansion $\alpha= 10.5\times10^{-6}\ K^{-1}$

We need to calculate the difference in the length of the bridge

Using formula of the difference in the length

$\Delta L=L\alpha\Delta T$

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Put the value into the formula

$\Delta L=1000\times10.5\times10^{-6}(40^{\circ}-0^{\circ})$

$\Delta L=0.42\ m$

Hence, The difference in the length of the bridge is 0.42 m.

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3 years ago