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AlladinOne [14]
3 years ago
8

I NEED HELP ASAP!! PLEASE

Physics
1 answer:
Kisachek [45]3 years ago
7 0

Answer:

Acceleration = -3m/s²

Explanation:

Given the following data;

Initial velocity = 19m/s

Final velocity = 3m/s

Time = 2secs

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time. Mathematically, acceleration is given by the equation;

Acceleration (a) = \frac{final \; velocity  -  initial \; velocity}{time}

Substituting into the equation, we have;

a = \frac{3 - 9}{2}

a = \frac{-6}{2}

Acceleration = -3m/s²

The value for her acceleration is negative because she is decelerating i.e her final velocity is lower than her initial velocity.

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julia-pushkina [17]
<h2>Answer: electromagnetic spectrum </h2>

The electromagnetic spectrum is the set of electromagnetic radiations distributed in their different frequencies or wavelengths, which in turn are related to their energy.

If we go from the smallest wavelengths known up to now (because according to physics the electromagnetic spectrum is infinite and continuous) to the longest, the electromagnetic spectrum covers the following radiations:

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6 0
3 years ago
The Cosmoclock 21 Ferris wheel in Yokohama City, Japan, has a diameter of 100 m. Its name comes from its 60 arms, each of which
emmainna [20.7K]

Answer:

Explanation:

A ) angular velocity ω = 2π / T

= 2 x 3.14 / 60

= .10467 rad / s

linear velocity v = ω R

=  .10467 x 50

= 5.23 m / s

centripetal force = m v² / R

= mg v² / gR

= 834 x 5.23² / 9.8 x 50

= 46.55 N

B )

apparent weight

= mg - centripetal force

= 834 - 46.55

= 787.45 N

C ) apparent weight

= mg + centripetal force

= 834 + 46.55

= 880.55 N.

D )

For apparent weight to be zero

centripetal force = mg

mg = mv² / R

v² = gR

= 9.8 x 50

= 490

v = 22.13 m /s

time period of revolution

= 2π R /v

2 x 3.14 x 50 / 22.13

= 14.19 s  

8 0
3 years ago
How high a hill can a car coast up (engine disengaged) if work done by friction is negligible and
aev [14]

Answer:

h= 46.66 m

Explanation:

Given that

Initial speed of the car ,u = 110 km/h

We know that

1 km/h= 0.277 m/s

u= 30.55 m/s

lets height gain by car is h.

The final speed of the car will be zero at height h.

v²=u²- 2 g h

v= 0 m/s

0²=30.55²- 2 x 10 x h           ( g = 10 m/s²)

h= 46.66 m

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3 years ago
The temperature of a body falls from 30°C to 20°C in 5 minutes. The air
natulia [17]

Answer:

15.88°C I am not 100% sure this is right but I am 98% sure this IS right

7 0
3 years ago
When electrons are lost, a ( )
Tcecarenko [31]

When electrons are lost a positive ion is formed. When electrons are gained, a negative ion is formed. I hope this helps

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