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3 years ago

I NEED HELP ASAP!! PLEASE

Physics

1 answer:

Kisachek [45]3 years ago

7 0

Answer:

Acceleration = -3m/s²

Explanation:

Given the following data;

Initial velocity = 19m/s

Final velocity = 3m/s

Time = 2secs

To find the acceleration;

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time. Mathematically, acceleration is given by the equation;

$Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation, we have;

$a = \frac{3 - 9}{2}$

$a = \frac{-6}{2}$

Acceleration = -3m/s²

The value for her acceleration is negative because she is decelerating i.e her final velocity is lower than her initial velocity.

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1. *A car is going over the top of a hill whose curvature approximates a circle of radius 200 m. At

Greeley [361]

Answer:

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s

Explanation:

The given parameters are;

The curvature of the hill, r = 200 m

Due to the velocity, v, the occupants weight = 20% less than the normal weight

The outward force of an object due to centripetal (motion) force is given by the following equation;

$F_c = \dfrac{m \times v^2}{r}$

Where;

r = The radius of curvature of the hill = 200 m

Given that the weight of the occupants, W = m × g, we have;

$F_c = 0.2 \times W = 0.2 \times m \times g$

$\therefore 0.2 \times m \times g = \dfrac{m \times v^2}{r}$

v = √(0.2 × g × r)

By substitution, we have;

v = √(0.2 × 9.81 × 200) ≈ 19.81

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.

3 0

3 years ago

A tuned mass damper for a skyscraper consists of a mass–spring system with spring constant 0.288 M/m. What should be its mass if

Morgarella [4.7K]

Answer:

m = 0.255kg

Explanation:

from the formular of a mass - spring system

T = 2π√m/k

making m as the subject of formular

m = T² k/4π²

T =5.91s

k = 0.288 N/m

m = 10.059/39.489

m = 0.255kg

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4 years ago

You push a heavy crate down a ramp at a constant velocity. Only four forces act on the crate. Which force does the greatest magn

Brilliant_brown [7]

The friction force does the greatest magnitude of work on the crate

Consider all four forces. The normal force does no work at all, since there is no motion in the direction of that force, perpendicular to the ramp. The force of gravity is smaller than the force of friction, since you still need to push the crate to get constant velocity. The force of you pushing is also smaller than the force of friction, since you are moving down a ramp, and are therefore assisted by gravity. Therefore the force doing greatest magnitude of work is the force of friction. Note that, even though the frictional work is negative, it still has the greatest magnitude

Learn more about friction force here:

brainly.com/question/4618599

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2 years ago

The center of gravity method is used to ________ travel time

icang [17]

Answer:

minimizes

Explanation:

The center of gravity method consists of an algorithm for the location of an installation considering existing ones. This is a very simple technique and is usually used to determine the location of intermediate warehouses and distribution points taking into account the distances that separate them and the contribution (in terms of utility, production or capacity) of each installation.

This location method takes into account three transport factors:

Ci: Transportation cost per unit

Vi: Volume transported from unit i

di: Distance traveled in the transport of the unit i

The primary objective of this method is to find the best location of a given installation of a company with respect to the other elements that make it up, to guarantee the minimum possible time and the minimum Total Transportation Cost.

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3 years ago

Difference between elastic and inelastic collisions

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An elastic collision is where there is no loss of kinetic energy in the collision. Momentum is conserved saved in inelastic collisions, but cannot track the kinetic energy through the collision since some of it is changed into other forms of energy.

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3 years ago