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Oduvanchick [21]
3 years ago
9

Calculate the grams of CaCl2 necessary to make a 0.15M solution.

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
8 0

Answer:

Gram molecular mass = 40 + (35.5)2 = 111g

Mass of CaCl_2 in 1 mole = 111g

Mass of CaCl_2 in 0.15 mole = 111 × 0.15 = 16.65 g

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The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is ________. the density of the sol
Thepotemich [5.8K]
The answer:
all that we search for is the number of mole of HCl and the number of mole of C2H6O

M(HCl) = 5.5g/ mole of HCl , so mole of HCl = 5.5/M(HCl), where M(HCl) is the molar mass.
M(HCl) = 1+ 36.5= 37.5 

moles of HCl = 5.5/37.5=0.14 

M(C2H6O) = 200g / moles of C2H6O, so moles of C2H6O=200g / M(C2H6O)

M(C2H6O)= 2x12+ 6 + 16=46,

moles of C2H6O=200g / 46 =<span>4.35 </span><span> moles 
</span>
the sum of the moles is    0.14 + <span>4.35 </span> = 4.501 moles

finally,  <span>The mole fraction of hcl in a solution prepared by dissolving 5.5 g of hcl in 200 g of c2h6o is 0.031
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