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3 years ago

11

In molecular oxygen (O=O) which atom is partially positive?

2 answers:

saveliy_v [14]3 years ago

4 0

the oxygen atom

Explanation:

Water is a molecular compound consisting of polar molecules that have a bent shape. The oxygen atom acquires a partial negative charge while the hydrogen atom acquires a partial positive charge.

Ivanshal [37]3 years ago

3 0

Answer:

Carbon

Explanation:

oxygen is more electronegative than carbon, the electrons will spend more time around the oxygen atom giving it a partially negative charge while the carbon will become partially positive. Some atoms retain lone (unbonded) pairs of electrons when they are part of a covalent complex.

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Carbohydrates are made up of carbon, hydrogen, and __________.

Rudik [331]

Oxegan ........
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2 years ago

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Why does lithium form only lithium oxide and not peroxide or superoxide

Alexandra [31]

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8 0

3 years ago

Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh

Dima020 [189]

<u>Answer:</u> The $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

<u>Explanation:</u>

For the given chemical reaction:

$2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)$

Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> $ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V$ ( × 2)

<u>Reduction half reaction:</u> $Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=1.36-(0.954)=0.406V$

To calculate standard Gibbs free energy, we use the equation:

$\Delta G^o=-nFE^o_{cell}$

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

$E^o_{cell}$ = standard cell potential = 0.406 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J$

Hence, the $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

4 0

3 years ago

"What volume of" a 0.300 M BaF2 "solution is needed to prepare" 240.0 mL of a 0.100 M F- solution

zhannawk [14.2K]

Use M x V = M' x V'

0.300 x V = 0.100 x 250

V = .......... ml

6 0

3 years ago

Clear selection

marin [14]

The molarity of the acid given the data from the question is 0.30 M

<h3>Balanced equation </h3>

2HNO₃ + Ba(OH)₂ —> Ba(NO₃)₂ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, HNO₃ (nA) = 2
The mole ratio of the base, Ba(NO₃)₂ (nB) = 1

<h3>How to determine the molarity of the acid</h3>

From the question given above, the following data were obtained:

Volume of acid, HNO₃ (Va) = 39.7 mL
Volume of base, Ba(NO₃)₂ (Vb) = 24 mL
Molarity of base, Ba(NO₃)₂ (Cb) = 0.250 M
Molarity of acid, HNO₃ (Ma) =?

MaVa / MbVb = nA / nB

(Ma × 39.7) / (0.25 × 24) = 2

(Ma × 39.7) / 6 = 2

Cross multiply

Ma × 39.7 = 6 × 2

Ma × 39.7 = 12

Divide both side by 39.7

Ma = 12 / 39.7

Ma = 0.30 M

Learn more about titration:

brainly.com/question/14356286

#SPJ1

8 0

1 year ago