A vice, you can tighten it and then work on what is held in it without having to hold it still or in the position you want.
I have 5
1. the work together
2. they produce things
3. they help something or someone
4. they send things to locations
5. packaging department
Answer:
Although cadmium usually has an oxidation state of +2, it also exists in the +1 state. Cadmium and its congeners are not always considered transition metals, in that they do not have partly filled d or f electron shells in the elemental or common oxidation states.
Explanation:
<u>Answer:</u> The balanced chemical equation is written below and 
for the reaction is -160.6 J/K
<u>Explanation:</u>
When calcium hydroxide reacts with sulfur dioxide, it leads to the formation of calcium sulfate and water molecule.
The chemical equation for the reaction of calcium hydroxide and sulfur dioxide follows:
To calculate the entropy change of the reaction, we use the equation:
![\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{products}]-\sum [n\times \Delta S^o_{reactants}]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20S%5Eo_%7Bproducts%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20S%5Eo_%7Breactants%7D%5D)
For the given reaction:
![\Delta S^o_{rxn}=[(1\times \Delta S^o_{CaSO_3(s)})+(1\times \Delta S^o_{H_2O(l)})]-[(1\times \Delta S^o_{Ca(OH)_2(s)})+(1\times \Delta S^o_{SO_2(g)})]](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%5CDelta%20S%5Eo_%7BCaSO_3%28s%29%7D%29%2B%281%5Ctimes%20%5CDelta%20S%5Eo_%7BH_2O%28l%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20S%5Eo_%7BCa%28OH%29_2%28s%29%7D%29%2B%281%5Ctimes%20%5CDelta%20S%5Eo_%7BSO_2%28g%29%7D%29%5D)
Taking the standard entropy change values:
Putting values in above equation, we get:
![\Delta S^o_{rxn}=[(1\times (101.4))+(1\times (69.9))]-[(1\times (83.4))+(1\times (248.5))]\\\\\Delta S^o_{rxn}=-160.6J/K](https://tex.z-dn.net/?f=%5CDelta%20S%5Eo_%7Brxn%7D%3D%5B%281%5Ctimes%20%28101.4%29%29%2B%281%5Ctimes%20%2869.9%29%29%5D-%5B%281%5Ctimes%20%2883.4%29%29%2B%281%5Ctimes%20%28248.5%29%29%5D%5C%5C%5C%5C%5CDelta%20S%5Eo_%7Brxn%7D%3D-160.6J%2FK)
Hence, the balanced chemical equation is written above and for the reaction is -160.6 J/K
1) We know that rtp = number of moles × 24
= 0.25 × 24
= 6 dm³
Therefore the volume of 0.25 moles of gas at rtp is A) 6 dm³
3.1) Amount of Copper = 20 tonnes
Amount of pure copper from impure copper = 18 tonnes
Purity of copper = (Pure copper/ impure copper) × 100
= (18 / 20) × 100
= 18 × 5
= 90 %
Therefore the purity of copper is 90%
3.2) We know that oxygen has 8 protons and 8 neutrons, so the weight of oxygen molecule is 8 + 8 = 16 u
So, one mole of oxygen weighs 16 g, so 2 moles weigh 2 × 16 = 32 grams
But oxygen is diatomic so the weight is 32 × 2 = 64 grams
Therefore the weight of 2 moles of oxygen is 64 grams
3.3) Concentration of solution = Amount of solute/volume
= 4 moles/ 2 dm³
= 4 / 2
= 2 mol/dm³
Therefore the concentration of a solution containing 4 moles in 2 dm³ of solution is 2 mol/dm³
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Extremely sorry for the late answer
