What is the solute in the mixture of muddy water
1 answer:
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Answer:
0.0008 m
Explanation:
We are given that 0.080 cm
We have to convert 0.080 cm into meter
To find the value of 0.080 cm in meter we are using unitary method
We know that
100 cm =1 m
1 cm =
Therefore, 0.080 cm =
0.080 cm =
0.080 cm =
0.08cm=0.0008 m
Hence, the value of 0.080 cm is equal to 0.0008 meter .
The question is incomplete, complete question is :
Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? ( for HF is
.)
[HF] = 0.280 M
Express your answer to two decimal places.
Answer:
The pH of an 0.280 M HF solution is 1.87.
Explanation:3
Initial concentration if HF = c = 0.280 M
Dissociation constant of the HF =
Initially
c 0 0
At equilibrium :
(c-x) x x
The expression of disassociation constant is given as:
Solving for x, we get:
x = 0.01346 M
So, the concentration of hydrogen ion at equilibrium is :
The pH of the solution is ;
The pH of an 0.280 M HF solution is 1.87.