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3 years ago

Which part of the mantle is still a solid but flows like a thick, heavy liquid?

Chemistry

2 answers:

Inga [223]3 years ago

4 0

Answer:

asthenosphere

Explanation:

Aesthenosphere is the uppermost part of the mantle and it is a region known for it high viscosity. The aesthenosphere is like a thick and heavy liquid. The next layer above the aesthenosphere is the lithosphere.

The aesthenosphere is what drive convection and plate tectonic . Convection talks about when less dense material rises and more dense material sinks.

The aesthenosphere through convection allows the lithospheric plate to move on it and this is what causes deformation and ductility of various rock bodies. This region plays a major role in plate tectonic as they determine how the plate are been separated into different parts.

This aesthenosphere is the region were molten magma migrate to the earth surface. The molten magma might erupt through volcano to the earth surface due to pressure .

marusya05 [52]3 years ago

3 0

Hello!

Your answer is A, asthenosphere

The asthenosphere is a part of the mantle. It helps move the plates in the Earth.

It is below the lithosphere, between 80 and 200 km below the surface.

Therfore, the asthenosphere is the part of the mantle that is still a solid but flows like a thick, heavy liquid.

Hope this helps!

Have a great day!

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2 years ago

The majority of water molecules moving across plasma membranes by osmosis do so via a process that is most similar to ____.

ValentinkaMS [17]

Answer:

The answer is Facilitated Diffusion

Explanation:

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2 years ago

Tell uses of nitrogen

Aleksandr [31]

Answer:

Hello

Preservation of Food. Nitrogen gas is used to help with food preservation by preventing oxidative damage leading to food spoiling.
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Explanation:

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6 0

3 years ago

Dinitrogen tetraoxide, N2O4, decomposes to nitrogen dioxide, NO2, in a first-order process. If k = 1.5 x 103 s-1 at 5 ºC and k =

Arada [10]

Answer:

The activation energy for the decomposition = 33813.28 J/mol

Explanation:

Using the expression,

$\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )$

Wherem

$k_1\ is\ the\ rate\ constant\ at\ T_1$

$k_2\ is\ the\ rate\ constant\ at\ T_2$

$E_a$ is the activation energy

R is Gas constant having value = 8.314 J / K mol

Thus, given that, $E_a$ = ?

$k_2=4.0\times 10^3s^{-1}$

$k_1=1.5\times 10^3s^{-1}$

$T_1=5\ ^0C$

$T_2=25\ ^0C$

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (5 + 273.15) K = 278.15 K

T = (25 + 273.15) K = 298.15 K

$T_1=278.15\ K$

$T_2=298.15\ K$

So,

$\ln \frac{1.5\times 10^3}{4.0\times 10^3}\:=-\frac{E_{a}}{8.314}\times \left(\frac{1}{278.15}-\frac{1}{298.15}\right)$

$E_a=-\ln \frac{1.5\times \:10^3}{4.0\times \:10^3}\:\times \frac{8.314}{\left(\frac{1}{278.15}-\frac{1}{298.15}\right)}$

$E_a=-\frac{8.314\ln \left(\frac{1.5\times \:10^3}{4\times \:10^3}\right)}{\frac{1}{278.15}-\frac{1}{298.15}}$

$E_a=-\frac{689483.53266 \ln \left(\frac{1.5}{4}\right)}{20}$

$E_a=33813.28\ J/mol$

The activation energy for the decomposition = 33813.28 J/mol

8 0

2 years ago

Finding the pH for [H+] = 9.4 * 10-3 M?

saul85 [17]

Answer:

pH = 2.0

Explanation:

To find the pH of a solution, take the -log[H+]. In this case, the -log(9.4 x 10^-3) equals 2.02687 which makes 2.0 when accounting for significant figures.

3 0

2 years ago