Mass of KNO₃ : = 40.643 g
<h3>Further explanation</h3>
Given
28.5 g of K₃PO₄
Required
Mass of KNO₃
Solution
Reaction(Balanced equation) :
2K₃PO₄ + 3 Ca(NO₃)₂ = Ca₃(PO₄)₂ + 6 KNO₃
mol K₃PO₄(MW=212,27 g/mol) :
= mass : MW
= 28.5 : 212,27 g/mol
= 0.134
Mol ratio of K₃PO₄ : KNO₃ = 2 : 6, so mol KNO₃ :
= 6/2 x mol K₃PO₄
= 6/2 x 0.134
= 0.402
Mass of KNO₃ :
= mol x MW KNO₃
= 0.402 x 101,1032 g/mol
= 40.643 g
To solve this problem, the dilution equation (M1 x V1 = M2 X V2) must be used. The given values in the problem are M1= 12.0 M, V1= 30 mL, and M2= 0.160 M. To solve for V2,
V2=M1xV1/M2
V2= (12x30)/0.16
V2= 2,250 mL.
The correct answer is 2.25 L.
Heat the sulfuric acid solution and adding copper carbonate in it.
<h3>Improvement require in this experiment</h3>
The method could be improved by heating sulfuric acid solution and add copper carbonate into the solution of sulfuric acid. Add the copper carbonate until it is present in excess amount. After that filter the extra amount of copper carbonate so in this way the blue copper sulfate crystals are produced.
Learn more about copper here: brainly.com/question/3157958
The balanced chemcial equation is B. So to do single, we need to look at where would Li stand on the metals chart (For my class we have a chart to see which element is the highest on the metals chart) . So since Li is higher, F needs to go with Li, leaving Ba alone.
I hope this helps you!
