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Stels [109]
3 years ago
14

Greatest common factor of 45 51 63

Mathematics
1 answer:
k0ka [10]3 years ago
8 0
45|3\\15|3\\.\ 5|5\\.\ 1|\\45=\fbox3\times3\times5\\\\51|3\\17|17\\.\ 1|\\51=\fbox3\times17\\\\63|3\\21|3\\.\ 7|7\\.\ 1|\\63=\fbox3\times3\times7\\\\GCF(45;\ 51;\ 63)=\fbox3
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What is the surface area of the right cone below?
olga2289 [7]
B. 4967 units idjdnndndndnndndndnndnd
3 0
3 years ago
The net worthw(t) of a company is growing at a rate of′(t) = 2000−121t2dollarsper year, wheretis in years since 1990.(a) If the
stiv31 [10]

Answer:

The worth of the company in 2000 is $56,000.

Step-by-step explanation:

The growth rate of the company is:

f'(t)=2000-12t^{2}

To determine the worth of the company in 2000, first compute the change in the net worth during the period 1990 (<em>t</em> = 0) to 2000 (<em>t</em> = 10) as follows:

\int\limits^{10}_{0} {2000-12t^{2}} \, dt =\int\limits^{10}_{0} {2000} \, dt-12\int\limits^{10}_{0} {t^{2}} \, dt=2000 |t|^{10}_{0}-12|\frac{t^{3}}{3}|^{10}_{0}\\=(2000\times10)-(4\times10^{3})\\=20000-4000\\=16000

The increase in the company's net worth from 1990 to 2000 is $16,000.

If the company's worth was $40,000 in 1990 then the worth of the company in 2000 is:

Worth in 2000 = Worth in 1990 + Net increase in company's worth

                        =40000+16000\\=56000

Thus, the worth of the company in 2000 is $56,000.

4 0
3 years ago
A washer and a dryer cost $676 combined. The washer costs $74 less than the dryer. What is the cost of the dryer?
Arlecino [84]

Answer: The dryer cost $375.

Step-by-step explanation:

676 - 74 = 602

602/2 = 301

301 + 74 = 375

3 0
3 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
A movie theater charges $5 for an adult ticket and $2 for a child's ticket. One Saturday, the theater sold 785 tickets for $3280
Nadya [2.5K]

Answer:

5x + 2y = 3280

x+y = 785

x = 785 - y

5*(785 - y) + 2y = 3280

3925 - 5y + 2y = 3280

3925 - 3280 - 3y = 0

645 = 3y

y=645/3=215

x=785-215 = 570

Adults - 570 tickets, childs - 215 tickets.

570*5 + 215*2 = 3280

570 adult and 215 child and 3,280 in total

if i could get brainliest that would be great

6 0
3 years ago
Read 2 more answers
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