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lidiya [134]
3 years ago
6

What is the domain of this function {(-3, 4), (-1, 3), (0, 4), (3, 6).

Mathematics
1 answer:
Nikitich [7]3 years ago
8 0
The domain is {3, -1, 0, 3}.
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Describe how the graph of the parent function y= √x is transformed when graphing y= 3 √x-6. The graph is translated 6 units ____
irga5000 [103]

The Answer: is ( Right . )

For the second answer is ( reflected over the x axis . )

The third one is stretch by a factor of 3 .

the fourth one is graph A

Step-by-step explanation:

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4 years ago
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Find the present value of $10000 if interest is paid at a rate of 8% per year compounded annually for 3 years?
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10,000*0.08*3= <span>$2400.00</span>
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3 years ago
A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

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3 years ago
How do I resolve this? <br> Como resuelvo esto?
Nikolay [14]

\bf \textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\ -----\\ A=144\pi  \end{cases}\implies 144\pi =\pi r^2\implies \cfrac{144\pi }{\pi }=r^2 \\\\\\ 144=r^2\implies \sqrt{144}=r\implies \boxed{12=r} \\\\\\ \textit{circumference of a circle}\\\\ C=2\pi r\qquad \qquad C=2\pi \boxed{12}\implies C=24\pi

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Luke hiked 6 1/4 miles. Joana hiked 2 1/ 5 times as far. how far did joana hike?​
mel-nik [20]

Answer:

13.75 or 13 3/4

Step-by-step explanation:

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4 years ago
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