Answer:
1728/ 125
Step-by-step explanation:
The ratio of corresponding lengths of the figures = ratio of the square root of their areas.
So ratio of lengths = 12/5.
Now volume is 3 dimensional so the ratio is the cube of the lengths
= 12^3/5^3
= 1728/ 125.
Given:
ABCD is a quadrilateral
AC = 12, DE = 4 and FB = 5
To find:
The area of the polygon.
Solution:
AC bisects the quadrilateral into two triangles.
Area of triangle:
<u>Area of triangle DAC:</u>
Area of triangle DAC = 24 square units.
<u>Area of triangle BAC:</u>
Area of triangle BAC = 30 square units.
Area of polygon = Area of triangle DAC + Area of triangle BAC
= 24 square units + 30 square units
= 54 square units
The area of the polygon is 54 square units.
Try to divide 62.01÷ 9 and then do it with the other one
For this case we have the following equation:
h = -16t ^ 2 + 32t + 6
Deriving we have:
h '= -32t + 32
We equal zero and clear t:
-32t + 32 = 0
32t = 32
t = 32/32
t = 1 s
Then, the maximum height is given by:
h (1) = -16 * (1) ^ 2 + 32 * (1) + 6
h (1) = 22 feet
Answer:
It takes the ball to reach its maximum height about:
t = 1 s
The ball's maximum height is:
h (1) = 22 feet
Answer: This hard behind question
Step-by-step explanation:
