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Hitman42 [59]
3 years ago
6

16 more than one third of a number w

Mathematics
1 answer:
GaryK [48]3 years ago
4 0
If you are looking to turn it into an expression:

1/3w+16

or it could possibly be (if you are looking at inequalities):

1/3w<16
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Find the midpoint between −18 and 52.
Mama L [17]
Finding the midpoint between two points on a line involves three steps:

1. Find the distance between the two points
2. Find half of that distance
3. Either add that half to the lowest point, or subtract it from the highest point.

To find the distance between 52 and -18, we can take the absolute value of their difference. The reason we take the absolute value is to force the sign to be positive, since distances can never be negative. -18 - 52 = -70, and |-70| = 70.

Second, we find half of that distance, which in this case would be 70/2 = 35.

Finally, we add that value to -18 to find a midpoint of -18 + 35 = 17.
5 0
3 years ago
How do I solve 1 and 2?
LuckyWell [14K]
H=+15 m
v=+5 m/s
Ball hits the ground when h(t)=-15m
h(t)=-9.8t^2+vt+h
=>
-15=-9.8t^2+5t+15
9.8t^2-5t-30=0
Solve for t, using quadratic formula,
t=-1.513 or t=2.023
reject negative root due to context, so
t=2.023 seconds

2)
h(t)=-16t^2+20t+8
a. height before pitch is when t=0, or h(0)=8
b. highest point reached when h'(t)=-32t+20=0 => t=5/8 seconds
c. highest point is t(5/8)=-16(5/8)^2+20(5/8)+8=47/5=9.4 m
d. ball hits ground when h(t)=0 => solve t for h(t)=0
=> t=-0.3187 seconds or t=1.569 seconds.
Reject negative root to give
time to hit ground = 1.569 since ball was pitched.

5 0
3 years ago
Line segment AB has a length of 4 units. It is translated 2 units to the right on a coordinate plane to obtain line segment A′B′
olchik [2.2K]

Answer:

need help asap

Step-by-step explanation:

4 0
4 years ago
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
Find the slope of the line passing through (0,-5) and (-4, 7),
choli [55]

Answer:

m = -3

Step-by-step explanation:

The slope formula is y2 - y1 / x2 - x1

7 - -5 = 7 + 5 = 12

-4 - 0 = -4

12 / -4 = -3

I hope this helps :))

7 0
3 years ago
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