The two parallelograms in the graph below are similar. Which sequence of transformations proves that the parallelograms are simi
lar? A rotation 270° clockwise about the origin followed by a dilation with scale factor 5 A rotation 270° clockwise about the origin followed by a dilation with scale factor A rotation 90° clockwise about the origin followed by a dilation with scale factor A rotation 180° clockwise about the origin followed by a dilation with scale factor 5
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THE QUESTION CAN BE WRITTEN AS THIS;
It is given that ∠ABC and ∠CBD are a____________ So, m∠ABC+m∠CBD=90° using the b____________. It is also given that m∠ABC=35°. Using the substitution property of equality, you have c________+ m∠CBD=90°. Therefore, using the subtraction property of equality, m∠CBD=55°
Answer:
a)COMPLIMENTARY ANGLE
b)DEFINITION OF COMPLEMENTARY ANGLES
c)35°+ m<CBD = 90 degrees.
Step by step Explanation:
a)It's given that <ABC and <CBD are (COMPLIMENTARY ANGLE)
We know that the Sum of Complementary angles equal to 90 degrees.Those angles don't have to be next to each other, just so long as the total is 90 degrees. That's why the Sum of m<ABC and m<CBD equals 90 degrees that is m<ABC + m<CBD = 90 degrees
b)using the (DEFINITION OF COMPLEMENTARY ANGLES) It is also given that m<ABC = 35 degrees.
c)Using substitution property of equality, you have (35°+ m<CBD = 90 degrees.)
If we subtract 35 from both sides, we get 35-35+ m<CBD = 90-35.
Therefore, m<CBD = 55 degrees.
PLEASE CHECK THE ATTACHED FIGURE TO SEE HOW THE QUESTION LOOKS LIKE
