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2 years ago

AICI, + NaNaCl + Al Did Al change oxidation number? yes No

Chemistry

1 answer:

mezya [45]2 years ago

3 0

Answer:

Yes, Al change oxidation number

Explanation:

$AlCl_3 +Na >NaCl+Al$

For a free element, oxidation number is 0.

Na and Al are free elements we find in the equation as they are not in combination with other elements.

For a compound, the sum of oxidation number of elements = 0.

We know oxidation number of chlorine is -1.

So let us find the oxidation number of Al in $AlCl_3$

Let x be the oxidation number of Al so,

$AlCl_3=x+(3\times-1)=0\\\\x-3=0\\\\ x= +3$

Oxidation number of Al in $AlCl_3$ is +3

Oxidation number of Al changes from +3 to 0.

Decrease in oxidation number indicates $AlCl_3$ is getting reduced in the reaction.

Na oxidation number increases from 0 to +1 shows Na is getting oxidised in the reaction

The change in oxidation number of the elements represents a redox reaction where both oxidation and reduction takes place simultaneously.

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Dovator [93]

Answer:

5 × 10^-4 L

Explanation:

The equation of the reaction is;

2KClO3 = 2KCl + 3O2

Number of moles of KClO3 = 13.5g/122.5 g / mol = 0.11 moles

From the stoichiometry of the reaction;

2 moles of KClO3 yields 3 moles of O2

0.11 moles of KClO3 yields 0.11 × 3/2 = 0.165 moles of oxygen gas

From the ideal gas equation;

PV= nRT

P= 85.4 × 10^4 KPa

V=?

n= 0.165

R= 8.314 J K-1 mol-1

T= 40+273 = 313K

V= 0.165 ×8.134 × 313/85.4 × 10^4

V=429.4/85.4 × 10^4

V= 5 × 10^-4 L

3 0

2 years ago

Need asap thank you

cupoosta [38]

Answer:

c.boron-11

Explanation:

The atomic mass of boron is 10.81 u.

And 10.81 u is a lot closer to 11u than it is to 10u, so there must be more of boron-11.

To convince you fully, we can also do a simple calculation to find the exact proportion of boron-11 using the following formula:

(10u)(x)+(11u)(1−x)100%=10.81u

Where u is the unit for atomic mass and x is the proportion of boron-10 out of the total boron abundance which is 100%.

Solving for x we get:

11u−ux=10.81u

0.19u=ux

x=0.19

1−x=0.81

And thus the abundance of boron-11 is roughly 81%.

6 0

2 years ago

Water changes from a liquid to a gas in the process of evaporation. true or false

Umnica [9.8K]

This it true because in the triangle of the transformation from solid, liquid, and gas
:0

4 0

3 years ago

Read 2 more answers

I have a brick, dimensions 4 cm tall, 9 cm wide, and 25 cm long, with a mass of 1250 g. What is the density?

Likurg_2 [28]

Answer:

1.389

Explanation:

P = m / V

m = 1250

V = 4x9x25 = 900

1250/900 = 1.388889

7 0

3 years ago

For a school event 1/6 of the athletic field is reversed for the fifth -grade classes the reserved part of the field is divided

SVETLANKA909090 [29]

Answer:

$\frac{1}{24}$

Explanation:

Given:

For a school event, 1/6 of the athletic field is reserved for the fifth -grade classes and the reserved part of the field is divided equally among the 4 fifth grade classes in the school.

To find: fraction of the whole athletic field reserved for each fifth class

Solution:

Fraction of the whole athletic field reserved for four fifth classes = $\frac{1}{6}$

So, fraction of the whole athletic field reserved for each fifth class = $\frac{1}{4}(\frac{1}{6})=\frac{1}{24}$

3 0

2 years ago