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Alecsey [184]
3 years ago
6

Write a function in terms of t that represents the situation. A company profit of $20,000 decreases by 13.4% each year

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

Answer:

P(t)=20000(0.866)^{t}

Step-by-step explanation:

we can use formula

P(t)=P_0(1-r)^{t}

where

P(t) is the profit after t years

Po is initial profit or profit is at t=0

r is decreasing rate

t is time in years

we are given

A company profit of $20,000 decreases by 13.4% each year

so,

Po=20000

r=13.4%=0.134

now, we can plug values

P(t)=20000(1-0.134)^{t}

we get

P(t)=20000(0.866)^{t}

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nikitadnepr [17]

The given statement is An integer is divisible by 100 if and only if its last two digits are zeros.

The two conditional statements that can be made are:

1) If an integer is divisible by 100 its last two digits are zeros.

This is a true statement. If a number is divisible by 100, it means 100 must be a factor of that number. When 100 will be multiplied by the remaining factors, the number will have the last two digits zeros.

<h3>What happen when last two digit of the number are 0?</h3>

2) If the last two digits of an integer are zeros, it is divisible by 100.

This is also true. If the last two digits are zeros, this means 100 is a factor of the integer. So the number will be divisible by 100.

Therefore, the two conditional statements that are formed are both true.

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Yes, it is. When the definition is separated into two conditional statements, both of the statements are true.

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Here is an example that disproves that:
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If x, y, and z are integers greater than 1, and (327)(510)(z) = (58)(914)(xy), then what is the value of x? (1) y is prime (2) x
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Answer:

1) 5

2) 5

Step-by-step explanation:

Data provided in the question:

(3²⁷)(5¹⁰)(z) = (5⁸)(9¹⁴)(x^y)

Now,

on simplifying the above equation

⇒ (3²⁷)(5¹⁰)(z) = (5⁸)((3²)¹⁴)(x^y)

or

⇒  (3²⁷)(5¹⁰)(z) = (5⁸)(3²⁸)(x^y)

or

⇒ (\frac{3^{27}}{3^{28}})(\frac{5^{10}}{5^8})z=x^y

or

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or

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we can say

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since, 2 is a prime number,

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x = 5

2) x is prime

since 5 is also a prime number

therefore,

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