The sum of x^2−3xy−y^2 and 2x^2+5xy−4y^2:
x^2−3xy−y^2 + 2x^2+5xy−4y^2
= 3x^2 + 2xy - 5y^2
From 6x^2−7xy+8y^2 subtract the sum of x^2−3xy−y^2 and 2x^2+5xy−4y^2:
6x^2−7xy+8y^2 - (3x^2 + 2xy - 5y^2)
= 6x^2−7xy+8y^2 - 3x^2 - 2xy + 5y^2
= 3x^2−9xy + 13y^2
Answer
3x^2−9xy + 13y^2
Answer:
Attached in file. I did this on paper, apologies if the PDF is blurry.
Answer:
The answer to your question is:
Step-by-step explanation:
8.-
A (8, 28)
B (0, 0)
m = (0- 28) / (0 - 8)
m = 7/2
y = (7/2) x
A( 16, 4)
B (0,0)
m = (0-4) / (0 - 16)
m = 1/4
y = (1/4) x
The constant of proportionality represents the slope of the line
9.-
a) (0,0) represents the start of the race.
b)
Horse A = 5 min
Horse B = 4 min
Answer:
Yes
Step-by-step explanation:
Test the equation by substituting 5 in for x:
19- 5 =14
14=14
TRUE
If I helped, a brainliest would be greatly appreciated!
