Answer:
119.38
Step-by-step explanation:
the circumference is πd so it is 19 X 2, which is 38, times π, which is 38π. this equals 119.38
I think it is fifty-four hundred
1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
Answer:
See below.
Step-by-step explanation:
a.
x = cost of adult ticket
y = cost of student ticket
cost of adult ticket is twice the cost of a student ticket
x = 2y
number of adult tickets = 64
number of student tickets = 132
cost of all adult tickets = 64x
cost of all student tickets = 132y
cost of all adult and student tickets combined: 64x + 132y
cost of all adult and student tickets combined: 1040
This gives us the equation:
64x + 132y = 1040
b.
Use substitution to solve the system of equations. Since x = 2y, where you see x in the second equation, substitute it with 2y.
64(2y) + 132y = 1040
128y + 132y = 1040
260y = 1040
y = 1040/260
y = 4
x = 2y = 2(4) = 8
adult ticket: $8
student ticket: $4