Y+Y+30=90
2Y=60 /:2
Y=30
PNQ=30°
QNO=30+30=60°
Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
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Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
Answer:
huh cant see the pic
Step-by-step explanation:
Answer:
It would be 68,70,72
Step-by-step explanation:
The sum of first and third of 3 consecutive number is 140 as 68+72 is 140.
68 is the first
72 is the third
They are all even numbers as well
