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Mademuasel [1]
4 years ago
15

What is the value of the expression 3y−zy+5z3y−zy+5z when y = 6 and z = 2?

Mathematics
2 answers:
WARRIOR [948]4 years ago
6 0
The valve of the expression would be 184
Vinvika [58]4 years ago
5 0
Plug in the numbers for y and z. 3(6)-6(2)+5(2). Solve. 18-12+(10). The answer is 16.
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There are two urns, each of them containing two blue balls and two red balls. We randomly draw two balls from the first urn and
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Answer: 50/50

Step-by-step explanation:

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3 years ago
4x25x27 associate property
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(4x25)x27
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3 years ago
The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as
bija089 [108]

Answer:

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(score of the 36 golfers was between 70 and 71)

\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}

P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%

P(70 \leq x \leq 71) = 47.7\%

0.477 is  the probability that the average score of the 36 golfers was between 70 and 71.

8 0
4 years ago
Sam has a budget of $24 to buy ham and cheese to make sandwiches. If he bought only ham, he could buy 8 lb. If he bought only ch
fomenos

Answer:

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
PLEASE HELP. WILL GIVE BRAINLEST
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Answer:

i would say A. The initial cost for renting a snowmobile is $75, with each hour of use costing an additional $25.

Step-by-step explanation:

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