Based on the information given, it should be noted that the residual for the two points will be 0.087 and -0.033 respectively.
<h3>How to find the residual.</h3>
From the complete information, the predicted value for the point (3, 0.42) will be:
= (0.091 × 3) + 0.060
= 0.0273 + 0.060
= 0.333
Therefore, the residual will be:
= 0.42 - 0.333 = 0.087
The predicted value for the point (3, 0.3) will be:
y = 0.091x + 0.060.
= (0.091 × 3) + 0.060.
= 0.333
Therefore, the residual will be:
= 0.3 - 0.333 = -0.033
Therefore, the residual for the two points will be 0.087 and -0.333 respectively.
Learn more about residuals on:
brainly.com/question/26255019
Answer:
CA = 22.6 ft
Step-by-step explanation:
For the known angle A, leg CA is the adjacent leg.
Side AB is the hypotenuse.
The trigonometric ratio that relates the adjacent leg tot eh hypotenuse is the cosine.
cos A = adj/hyp
cos 41° = CA/(30 ft)
CA = 30 ft * cos 41°
CA = 22.6 ft
It is given in the question that
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by
![V = x^2h cm^3](https://tex.z-dn.net/?f=V%20%3D%20x%5E2h%20cm%5E3)
And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.
Here we differentiate V with respect to t, and we use product rule, that is
![V = 2xh(dx/dt)+ x^2(dh/dt)](https://tex.z-dn.net/?f=V%20%3D%202xh%28dx%2Fdt%29%2B%20x%5E2%28dh%2Fdt%29)
Substituting the given values , we will get
[/tex]
![dV/dt = -288+144 = -144cm^3/min](https://tex.z-dn.net/?f=dV%2Fdt%20%3D%20-288%2B144%20%3D%20-144cm%5E3%2Fmin)
So at that moment, the volume is decreasing at the rate of
![144 cm^3/min](https://tex.z-dn.net/?f=144%20cm%5E3%2Fmin)
441614, rounded to the whole
Answer:
About 268.08
Step-by-step explanation: