If you release a weight and allow it to fall under the influence of gravity alone, what kind of motion will it experience?
2 answers:
You might be interested in
Answer:
Let's see the similarities between the two forces
* are proportional to the product of a magnitude, mass or charge
* They are inversely proportional to the square of the distance
* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.
The differences in them
* The electric force in much greater than the gravitational force
* The gravitational force is always attractive, the electrical force can be attractive or repulsive.
Explanation:
Let's start by calculating each force.
Gravitational force
F =
let's calculate
F = 6.67 10⁻¹¹ 1 1 / 1²
F = 6.67 10⁻¹¹ N
Electric force
F =
indicates that the charge is q = 10 C
F = 9 10⁹ 10 10 / 1²
F = 9 10¹¹ N
Let's see the similarities between the two forces
* are proportional to the product of a magnitude, mass or charge
* They are inversely proportional to the square of the distance
* They are long-range forces since zero is not made up to an infinite distance. The gravitational force is always attractive, the electrical force can be attractive or repulsive.
The differences in them
* The electric force in much greater than the gravitational force
* The gravitational force is always attractive, the electrical force can be attractive or repulsive.
Answer:
Radius of cross section, r = 0.24 m
Explanation:
It is given that,
Number of turns, N = 180
Change in magnetic field,
Current, I = 6 A
Resistance of the solenoid, R = 17 ohms
We need to find the radius of the solenoid (r). We know that emf is given by :
Since, E = IR
or
Area of circular cross section is,
r = 0.24 m
So, the radius of a tightly wound solenoid of circular cross-section is 0.24 meters. Hence, this is the required solution.