Answer:
10-16= -4 so, 1.0x-4 is -4. So the answer is -4.
Explanation:
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Initial velocity, u = 0
Final velocity, v = 60 m/s (at take off)
Duration of the acceleration, t = 4 s
Calculate average acceleration.
a = (v - u)/t
= (60 m/s)/(4 s)
= 15 m/s²
Calculate the distance traveled during acceleration.
s = ut + (1/2)*a*t²
= 0.5*(15 m/s²)*(4 s)²
= 120 m
Answer: 120 m
Answer:23 seconds
Explanation:
Acceleration(a)=3.87m/s^2
distance(d)=1020m
Initial velocity(u)=0
d=uxt + (axt^2)/2
1020=0xt + (3.87xt^2)/2
1020=(3.87xt^2)/2
Cross multiply
1020x2=3.87xt^2
2040=3.87xt^2
t^2=2040/3.87
t^2=527.13
t=22.95
Time(t) is approximately 23seconds
Answer:
The time required to send the data from Earth to Moon will be 1.28s while for a two way communication, to send it back to the earth, it will take double time i.e. <em>RTT = 2.56s </em>
Explanation:
Distance between Earth and Moon = 385,000 km = 3.85 x 10⁸m
Speed of data travel = speed of light ≈ 3 x 10⁸m/s
As, v=d/t
t=d/v
t=1.28s
RTT = Double of single way time taken = 2x1.28
<em><u>RTT=2.56s</u></em>