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sveticcg [70]
3 years ago
12

What is 271,403 rounded to the nearest hundred thousand .

Mathematics
2 answers:
MAXImum [283]3 years ago
5 0

271,403.00000

Step-by-step explanation:

Lapatulllka [165]3 years ago
4 0

Answer:

300,000

Step-by-step explanation:

If you look at it the number seven before two by 3 so every thing below it not going to matter

let me give you another example like 54,555  rounded to the nearest ten thousand for this one you would take the number in the ten thousand palce(5) and look at the number before it and get 50,000

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A map is drawn to a scale of 1 : 20 000.
Nesterboy [21]

Answer:

  • 0.625 cm²

Step-by-step explanation:

<u>Scale factor:</u>

  • k = 1/20000

When applied to the area consider k² as a scale factor.

<u>The actual area:</u>

  • 2.5 hectares = 25000 m² = 25000*100² cm² = 250000000 cm²

<u>The area on the map:</u>

  • 250000000 * (1/20000)² = 0.625 cm²
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3 years ago
Miriam is driving to Austin. This is what her gas gauge looks like when she stops for lunch. What fraction of her gas tank is fi
Andreas93 [3]

Answer:

Help me! My answer.

Step-by-step explanation:

4 0
3 years ago
Use the probability model above to determine the successful outcome’s contribution to the expected value of the return.
Keith_Richards [23]

Answer: Hence, Option 'D' is correct.

Step-by-step explanation:

Since we have given that

Probability of successful outcome = 0.7

Probability of unsuccessful outcome = 0.3

Amount he get for successful outcome = $900

Amount he lost for unsuccessful outcome = -$1800

We need to find the expected value of return when there is successful outcome:

P(Success)× Amount for successful

0.7\times \$900\\\\=\$630

Hence, Option 'D' is correct.

8 0
3 years ago
Please help me find the missing side lengths
Anna71 [15]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Charge q is one unit of distance away from the source charge s. Charge p is two times further away. The force exerted between S
finlep [7]

Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p

a. 1/2

b. 2 times

c. 1/4

d. 4 times

Answer:

4 times

Step-by-step explanation:

Given the following :

Distance between q and S (r) = 1 unit

Distance between P and S (r) = 2 × 1 unit = 2

According to coliumbs law:

F = Ke(q1q2) /r^2

Where F = electrostatic force, Ke = coloumbs constant

q1,q2 = charges, r = distance between two charges

For q and S :

Fsq = Ke(q1q2) / 1^2

Fsq = Ke(q1q2) - - - - - equation 1

For P and S :

Fsp = Ke(q1q2) / 2^2

Fsp = Ke(q1q2) / 4 - - - - - equation 2

Dibiding equation 1 by equation 2

Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4

Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)

Fsq / Fsp = 4 / 1

Using cross multiplication

Therefore, Fsq = 4 × Fsp

7 0
3 years ago
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