A.
elements C H N
percentage composition 74.03 8.70 17.27
Molecular mass 12 1 14
# of mole 6.17 8.70 1.23
÷smallest mole 5.0 7.0 1.0
mole ratio 5 : 7 ; 1
THE EMPERICAL FORMUKLA FOR A. IS C5H7O
NOTE: #of mole = percentage composition ÷ Mr
and the ÷ smallest mole is used to find the ratio...for the above question a. it is 1.23
and b. should be done using the same procedure
Answer:
22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C
Explanation:
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:
P * V = n * R * T
where R is the molar constant of the gases and n the number of moles.
In this case you know:
- R= 0.082

- T= 24 °C= 297 °K (being 0°C=273°K)
Replacing:

Solving:

n=0.708 moles
Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?

mass= 22.656 grams
<u><em>22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C</em></u>
Hello there.
<span>Natalie accelerates her skateboard along a straight path from 4 m/s to 0 m/s in 25.0 s. Find the acceleration.
</span><span>0.16 m/s2
</span>
Answer:- D. 
Explanations:- In chemical equations, (aq) stands for aqueous, (l) stands for liquid, (g) stands for gas and (s) stands for solid. In double replacement reactions, (aq) means soluble and (s) means insoluble that is precipitate.
Looking at all the equations, it is only the last equation that has a solid product and so this is the only precipitation reaction. A precipitate for Iron(II)carbonate is formed in it.
2.0 MOL is the correct answer I believe