Question

Suppose you have a 0.10 M solution of AlBr3. What is the concentration of each ion? A. 0.10 M Al3+ ions and 0.30 M Br- ions B. 0.30 M Al3+ ions and 0.10 M Br- ions C. 0.10 M Al3+ ions and 0.033 M Br- ions D. 0.033 M Al3+ ions and 0.033 M Br- ions

Answer 1

Answer: The concentration of $Al^{3+}$ ions is 0.10 M and that of $Br^-$ ions is 0.30 M

Explanation:

We are given:

Concentration of $AlBr_3$ = 0.10 M

The chemical equation for the ionization of aluminium bromide follows:

$AlBr_3\rightarrow Al^{3+}+3Br^-$

1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions

So, concentration of aluminium ions = 0.10 M

Concentration of bromide ions = $[(3\times 0.1)]=0.3M$

Hence, the concentration of $Al^{3+}$ ions is 0.10 M and that of $Br^-$ ions is 0.30 M