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4 years ago

The organic compound ketone contains which functional group?

Chemistry

2 answers:

shtirl [24]4 years ago

8 0

D on plato! #platofamily

soldi70 [24.7K]4 years ago

3 0

Ketones and aldehydes are simple compounds that contain a carbonyl group (a carbon-oxygen double bond). They are considered "simple" because they do not have reactive groups like −OH or −Cl attached directly to the carbon atom in the carbonyl group, as in carboxylic<span> acids containing </span>

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How many liters will 5.00 moles of oxygen occupy at STP?

Sveta_85 [38]

Answer:

1 mole of any gas at STP occupies 22.4 liters of volume. Using this information, the volume occupied by any number of moles (or grams) can be determined.

Explanation:

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3 years ago

How many grams of calcium chloride were used if 2.485 grams of calcium oxalate monohydrate were produced, assuming a 100% yield.

DochEvi [55]

Answer:

54 G

Explanation:

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3 years ago

One gallon of gasoline in an automobiles engine produces on average 9.50 kg of carbon dioxide, which is a greenhouse gas; that i

vagabundo [1.1K]

Answer:

The value is $U =1.3908 *10^{11} \ kg$

Explanation:

From the question we are told that

mass of carbon dioxide produced by one gallon of gasoline is $m = 9.50 \ kg$

The number of cars is $N = 40 \ million = 40 *10^{6} \ cars$

The distance covered by each car is $d = 7930 \ mi$

The rate is $R = 23.6 \ mi/ gallon$

Generally the amount of gasoline used by one car is mathematically represented as

$G = \frac{d}{R}$

=> $G = \frac{7930}{23.6}$

=> $G = 366 \ gallons$

Generally the amount of gasoline used by N cars is

$H = N * G$

=> $H = 40*10^{6} * 366$

=> $H = 1.464*10^{10} \ gallons$

Generally the annual production of carbon dioxide is mathematically represented as

$U = m * H$

=> $U =9.50 * 1.464*10^{10}$

=> $U =1.3908 *10^{11} \ kg$

8 0

4 years ago

Materials with_____ bonds tend to be more easily scratched

iren [92.7K]

Materials with ionic bonds tend to be more easily scratched.

4 0

4 years ago

Select the correct set of quantum numbers (n, l, ml, ms) for the first electron removed in the formation of a cation for stronti

matrenka [14]

Answer:

5,0,0,-1/2

Explanation:

The quantum numbers are a way to characterize the electrons, and so, identify the region that it's more probable to find it (orbital). They are:

- Principal quantum number (n): represents the shell or level, and varies from 1 to 7, and are represented by the letter K, L, M, N, O, P, and Q.

- Azimuthal quantum number (l): represents the subshell or sublevel, and is represented by 0,1,2,3.., and for the letters s, p, d, f,...

- Magnetic quantum number (ml): represents the orbital. It varies from -l to +l passing by 0. Each orbital can have 2 electrons.

- Spin quantum number (ms): represents the spin of the electron. It can be +1/2 or -1/2.

The strontium has an atomic number equal to 38, by the Linus Pauling's diagram, the electronic distribution is:

1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²

The valence electron is at the subshell 5s, which has only one magnetic quantum number: 0. Because it has 2 electrons, the first one has spin =1/2, and the other -1/2. So the first electron of the formation of cation has quantum numbers:

n = 5; l = 0; ml = 0; ms = -1/2

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3 years ago